The statements from both Technicians A and B are correct.
Answer: Option C
<u>Explanation:</u>
A typical MAP sensors comprises with a ceramic or silicon wafers, sealed with an ideal vacuum on one side and a suction manifold on the other. When the engine (motor) vacuum varies, the differential pressure across the board changes the output voltage or frequency to the MAP sensor. So, sensor vacuum to be increased if injection pulse widths increase.
Most pressure sensors operate at 5 volts from a computer and return a signal (voltage or frequency) based on the pressure applied to the sensor (vacuum). When testing the MAP sensor, make sure that the vacuum hose and hose connections are tightly connected to the engine vacuum source. According to this, concluding that the statements from both technicians are correct.
Answer:
C I think so
Explanation:
ocean waves hitting a concert barrier that reduces their energy
Answer:
The value is 
Explanation:
From the question we are told that
The frequency of each sound is
The speed of the sounds is 
The distance of the first source from the point considered is 
The distance of the second source from the point considered is 
Generally the phase angle made by the first sound wave at the considered point is mathematically represented as
![\phi_a = 2 \pi [\frac{a}{\lambda} + ft]](https://tex.z-dn.net/?f=%5Cphi_a%20%3D%20%202%20%5Cpi%20%5B%5Cfrac%7Ba%7D%7B%5Clambda%7D%20%20%2B%20ft%5D)
Generally the phase angle made by the first sound wave at the considered point is mathematically represented as
Here b is the distance o f the first wave from the considered point
Gnerally the phase diffencence is mathematically represented as
=> ![\Delta \phi = \frac{2\pi [ a - b]}{ \lambda }](https://tex.z-dn.net/?f=%5CDelta%20%20%5Cphi%20%20%20%3D%20%20%20%5Cfrac%7B2%5Cpi%20%5B%20a%20-%20b%5D%7D%7B%20%5Clambda%20%7D)
Gnerally the wavelength is mathematically represented as

=> 
=> 
=> ![\Delta \phi = \frac{2* 3.142 [ 4.40 - 4.0 ]}{ 0.611 }](https://tex.z-dn.net/?f=%5CDelta%20%20%5Cphi%20%20%20%3D%20%20%20%5Cfrac%7B2%2A%203.142%20%5B%204.40%20-%204.0%20%5D%7D%7B%20%200.611%20%20%7D)
=> 
Answer:
C. 0.2 Hertz
Explanation:
The frequency of a spring is equal to the reciprocal of the period:

where
f is the frequency
T is the period
For the spring in this problem,
T = 5 s
therefore, the frequency is

The change in surface area of Gaussian surface with radius (r) is 8πr.
<h3>
Electric field from Coulomb's law</h3>
The electric field experienced by a charge is calculated as follows;

where;
- E is the electric field
- Q is the charge
- r is the radius
The electric field reduces by a factor of 
<h3>Surface area of a Gaussian surface;</h3>
The surface area of a sphere is given as;

<h3>Change in area with r</h3>

Thus, the change in surface area of Gaussian surface with radius (r) is 8πr.
Learn more about area of Gaussian surfaces here: brainly.com/question/17060446