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VashaNatasha [74]
3 years ago
6

What will be the final velocity of a 5.0 g bullet starting from rest, if a net force of 45 N is applied over a time of 0.02s?

Physics
1 answer:
Wewaii [24]3 years ago
3 0

We know there’s a change in momentum due to a force applied over a time interval. Ft= m[v(final)-v(initial)]. Now simply plug in know values: (45)(0.02)=.005[v(final)-0]. Remember converting grams to kilograms. Solve for v final

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5.8 meters/second + 1.2 meters/second
Alex Ar [27]

Answer:7m/s

Explanation:

5.8+1.2

=7.

8 0
3 years ago
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An alarm clock has a resistance of 14,000 ohms and is plugged into a 120-volt outlet. How much power does the clock use?
yan [13]

Power used by the clock=1.03 W

Explanation:

resistance= 14000 ohm

voltage=120 V

The formula for the power is given by

P=\frac{V^{2}}{R}

P=(120)²/14000

P=1.03 W

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3 years ago
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An acorn falls from a branch located 9.8 m above the ground. After 1 s of falling, the acorn's velocity will be 9.8 m/s downward
goldenfox [79]

Answer:

The acorn hasn't hit the ground because it only falsl half of the branch distance from the ground

Explanation:

given information:

h =9.8

t =1 s

g = 9.8

the average speed

v = 1/2 gt²

   = 1/2 (9.8) (1)²

   = 4.8 m/s

the distance in 1s

h = v t

   = 4.8 (1)

   = 4.8 m

the acorn hasn't hit the ground because it only falsl half of the branch distance from the ground

   =

8 0
3 years ago
This is one of the four planets Mercury,Venus,Earth,and Mars, whose orbits lie nearest the Sun
galben [10]

Answer:

Mercury

Explanation:

Mercury is the closest planet to the sun followed be Venus. Though Mercury is the closest Venus is actually the hotest planet

6 0
3 years ago
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A speedboat increases its speed from 14.5 m/s to 29.3 m/s in a distance of 172 m.
dalvyx [7]

Answer:

a. Acceleration, a = 1.88 m/s²

b. Time, t = 7.87 seconds.

Explanation:

Given the following data;

Initial velocity, U = 14.5m/s

Final velocity, V = 29.3m/s

Distance, S = 172m

a. To find the acceleration of the speedboat;

We would use the third equation of motion;

V² = U² + 2aS

Substituting into the formula

29.3² = 14.5² + 2a*172

858.49 = 210.25 + 344a

344a = 858.49 - 210.25

344a = 648.24

a = 648.24/344

Acceleration, a = 1.88 m/s²

b. To find the time;

We would use the first equation of motion;

V = U + at

29.3 = 14.5 + 1.88t

1.88t = 29.3 - 14.5

1.88t = 14.8

Time, t = 14.8/1.88

Time, t = 7.87 seconds.

6 0
3 years ago
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