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3 years ago

2. Three numbers whose product is 64 are 2, 4,

Mathematics

2 answers:

Alenkasestr [34]3 years ago

5 0

Answer:

A) 0.8 X 3 X 1 = 2.4

B) 0.3 X 2 X 4 = 2.4

C) 0.4 + 1.5 +0.5 = 2.4

D) 2 + 0.3 + 0.1 = 2.4

Step-by-step explanation:

A) To get three numbers whose product is 2.4, we will have to find out by multiplying three different decimal numbers to see if we can get 2.4. In other words, we are looking for factors of 2.4.

We can start by dividing 2.4 by three.

This will give 0.8 ( which is one of the numbers)

Recall that 1 is also a number and any number multiplied by 1 is itself. We can take one to be our third number.

Our three numbers are 0.8 X 3 X 1 = 2.4

B) To get another set of numbers, we can simply choose to divide 2.4 by 4.

2.4 / 2 = 0.6.

we can also divide 0.6 into 2.

0.6 / 2 = 0.3

Our other three numbers can be 0.3 X 2 X 4 = 2.4

C) Three numbers which can sum up to 2.4 are

0.4 + 1.5 +0.5 = 2.4

D) To get another set of numbers, we can simply break 2.4 up into other simpler numbers.

2 + 0.3 + 0.1 = 2.4

UNO [17]3 years ago

5 0

Answer:

The answer is A

Step-by-step explanation:

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3 years ago

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11111nata11111 [884]

Answer:

The dimension of the open rectangular box is $8.216\times 4.216\times 1.392$ .

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is $V=l\times b\times h$

$V=(11-2x)\times (7-2x)\times x$

$V=4x^3-36x^2+77x$

Derivate w.r.t x,

$V'(x)=4(3x^2)-2(36x)+77$

$V'(x)=12x^2-72x+77$

The critical point when V'(x)=0

$12x^2-72x+77=0$

Solve by quadratic formula,

$x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}$

$x=4.607,1.392$

Derivate again w.r.t x,

$V''(x)=24x-72$

Now, $V''(4.607)=24(4.607)-72=38.568>0$ (+ve)

$V''(1.392)=24(1.392)-72=-38.592$ (-ve)

So, there is maximum at x=1.392.

The length of the box is $l=11-2x$

$l=11-2(1.392)=8.216$

The breadth of the box is $b=7-2x$

$b=7-2(1.392)=4.216$

The height of the box is h=1.392.

The dimension of the open rectangular box is $8.216\times 4.216\times 1.392$ .

The volume of the box is $V=l\times b\times h$

$V=8.216\times 4.216\times 1.392$

$V=48.217\ in.^3$

The volume of the box is 8.217 cubic inches.

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3 years ago

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katovenus [111]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

The center of measure calculated was the average or mean. To get the mean of a set of numbers, we have to add all the numbers given and then divide them by the numbers.

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