Some one please Help and Thank you <br>

2.2.<br> Name the two stages of photosynthesis

andre [41]

Answer:

1. Light-dependent stage

2. Light-independent stage or Calvin cycle

Explanation:

Photosynthesis is the process by which plants and other autotrophic organisms synthesize their food (glucose) in the presence of sunlight as energy source. However, this photosynthetic process, which is a metabolic reaction occurs in two stages namely; Light-dependent stage and Light-independent stage.

- The light dependent stage occurs in the thylakoid membrane of the chloroplast. It involves the synthesis of NADPH and ATP needed for the light independent stage of photosynthesis.

- The light independent stage also known as Calvin cycle occurs in the stroma of the chloroplast. This is the stage where glucose is synthesized using inorganic source of carbon (CO2).

6 0

3 years ago

Which of the following is the electron configuration of an atom in the ground state?

beks73 [17]

Answer:

(a) 1s2 2s1

Explanation:

Electron configurations of atoms are in their ground state when the electrons completely fill each orbital before starting to fill the next orbital.

<h3><u>Understanding the notation</u></h3>

It's important to know how to read and interpret the notation.

For example, the first part of option (a) says "1s2"

The "1" means the first level or shell
The "s" means in an s-orbital
The "2" means there are 2 electrons in that orbital

<h3><u></u></h3><h3><u>Other things to know about electron orbitals</u></h3>

It important to know which orbitals are in each shell:

In level 1, there is only an s-orbital
In level 2, there is an s-orbital and a p-orbital
in level 3, there is an s-orbital, a p-orbital, and a d-orbital <em>(things get a little tricky when the d-orbitals get involved, but this problem is checking on the basic concept -- not the higher level trickery)</em>

So, it's also important to know how many electrons can be in each orbital in order to know if they are full or not. The electrons should fill up these orbitals for each level, in this order:

s-orbitals can hold 2
p-orbitals can hold 6
d-orbitals can hold 10 <em>(but again, that's beyond the scope of this problem)</em>

<h3><u>Examining how the electrons are filling the orbitals</u></h3>

<u>For option (a):</u>

the 1s orbital is filled with 2, and
the 2s orbital has a single electron in it with no other orbitals involved.

This is in it's ground state.

<u>For option (b):</u>

the 1s orbital is filled with 2,
the 2s orbital is filled with 2,
the 2p orbital has 5 (short of a full 6), and
the 3s orbital has a single electron in it.

Because the 3s orbital has an electron, but the lower 2p before it isn't full. This is NOT in it's ground state.

<u>For option (c):</u>

the 1s orbital is filled with 2,
the 2s orbital has 1 (short of a full 2), and
the 2p orbital is filled with 6

Although the 2p orbital is full, since the 2s orbital before it was not yet full, this is NOT in it's ground state.

<u>For option (d):</u>

the 1s orbital has 1 (short of a full 2), and
the 2s orbital is filled with 2

Again, despite that the final orbital (in this case, the 2s orbital), is full, since the 1s orbital before it was not yet full, this is NOT in it's ground state.

6 0

2 years ago

a calorimeter contained 75.0 g of water at 16.95 C. A 93.3-g sample of iron at 65.58 C was placed in it, giving a final temperat

Nostrana [21]

Answer:- $\frac{382.69J}{0C}$ .

Solution:- Mass of Iron added to water is 93.3 g. Initial temperature of iron metal is 65.58 degree C and final temperature of the system is 19.68 degree C.

temperature change, $\Delta T$ for iron metal = 65.58 - 19.68 = 45.9 degree C

specific heat for the metal is given as 0.444 J per g per degree C.

let's calculate the heat lost by iron metal using the equation:

$q=mc\Delta T$

where, q is the heat energy, m is mass, c is specific heat and delta T is change in temperature. let's plug in the values and calculate q for iron metal:

$q=93.3g(45.9^0C)(\frac{0.444J}{g.^0C})$

q = 1901.42 J

Using same equation we will calculate the heat gained by water.

mass of water is 75.0 g.

$\Delta T$ for water = 19.68 - 16.95 = 2.73 degree C

specific heat for water is 4.184 J pr g per degree C. Let's plug in the values:

$q=75.0g(\frac{4.184J}{g.^0C})(2.73^0C)$

q = 856.674 J

Total heat lost by iron metal is the sum of heat gained by water and calorimeter.

So, heat gained by calorimeter = heat lost by iron metal - geat gained by water

heat gained by calorimeter = 1901.42 J - 856.674 J = 1044.746 J

Change in temperature for calrimeter is same as for water that is 2.73 degree C

For calorimeter, $q=C.\Delta T$

$C=\frac{q}{\Delta T}$

$C=\frac{1044.746J}{2.73^0C}$

$C=\frac{382.69J}{0C}$

So, the heat capacity of calorimeter is $\frac{382.69J}{0C}$ .

4 0

3 years ago

Which of the following weathering processes involves the constant freezing and thawing of water?

Artemon [7]

Frost wedging

Explanation:

Weathering is the physical disintegration and chemical decomposition of rocks to form sediments and soils.

Some agents of weathering are wind, water, glacier and gravity.

In physical weathering, rocks are broken down mechanically into smaller bit.
Freezing and thawing allows for the propagation of physical weathering.
Water within cracks will expand when they freeze significantly.
This will further expand and widen the cracks.
When the ice thaws the stress is relieved.
When the process continues on and on over the year, a rock will eventually break down.
This is common around the temperate and polar regions.

Learn more:

weathering brainly.com/question/876569

#learnwithBrainly

4 0

3 years ago

Atoms are generally held together by attraction between neutrons and protons (the strong interaction) and stabilized by electron

mezya [45]

Answer:

im pretty sure the answer is: alpha decay, beta decay, and gamma decay.

Explanation:

7 0

3 years ago

Some one please Help and Thank you ​

Some one please Help and Thank you