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2 years ago

What are the prevailing winds from the west toward the east called?

Physics

1 answer:

8_murik_8 [283]2 years ago

4 0

Answer:

The Coriolis Effect, in combination with an area of high pressure, causes the prevailing winds—the trade winds—to move from east to west on both sides of the equator across this 60-degree "belt."

Explanation:

if its wrong welp sorry that what i know,

You might be interested in

A person observing a flame is interested in the types of electromagnetic waves with slightly shorter and slightly longer wavelen

Nadya [2.5K]

Answer:

Ultra violet rays and infrared rays

Explanation:

The electromagnetic radiation in the order of increasing wavelength is given as

Gamma rays

X rays

Ultra violet rays

Visible radiation

Infrared rays

Microwaves

radiowaves

So, the radiations having wavelength more than the visible radiation are infrared radiations and the radiations which having the wavelength less then the visible radiation is Ultraviolet rays.

So, we observe ultra violet radiations and infrared radiations.

3 0

3 years ago

What is the wave length if the distance from the central bright region to the sixth dark fringe is 1.9 cm . Answer in units of n

Yuri [45]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The wavelength is $\lambda = 622 nm$

Explanation:

From the question we are told that

The distance of the slit to the screen is $D = 5 \ m$

The order of the fringe is m = 6

The distance between the slit is $d = 0.9 \ mm = 0.9 *10^{-3} \ m$

The fringe distance is $Y = 1.9 \ cm = 0.019 \ m$

Generally the for a dark fringe the fringe distance is mathematically represented as

$Y = \frac{[2m - 1 ] * \lambda * D }{2d}$

=> $\lambda = \frac{Y * 2 * d }{[2*m - 1] * D}$

substituting values

=> $\lambda = \frac{0.019 * 2 * 0.9*10^{-3} }{[2*6 - 1] * 5}$

=> $\lambda = 6.22 *10^{-7} \ m$

$\lambda = 622 nm$

8 0

2 years ago

If the sine of an angle is 4/7 what is the cosine of its complement.

kap26 [50]

Answer: 0.57

Explanation:

Let's begin by explaining that two angles are complementary when they sum is $90\°$ :

$\theta + \alpha=90\°$

Having this clear, let's find $\theta$ from the following trigonometric function:

$sin \theta=\frac{4}{7}$

$\theta=sin^{-1} (\frac{4}{7})=34.84 \°$

Now that we have the value of $\theta$ , let's find $\alpha$ :

$\alpha=90\°-\theta$

$\alpha=90\°-34.84 \°$

$\alpha=55.15\°$ This is the complement of angle $\theta$

Then, the cosine of the complement $\alpha$ is:

$cos \alpha=cos(55.15\°)$

$cos \alpha=0.57$ This is the answer

7 0

2 years ago

The coefficients of static and kinetic friction between a 50.0-kg box and a horizontal surface are 0.500 and 0.400 respectively.

natulia [17]

Answer:

1.08 m/s^2

Explanation:

The maximum value of static friction F_s = μ_s mg

where μ_s = coefficient of static friction

m= mass of box= 50kg

g= 9.81 m/s^2 , acceleration due to gravity

F_s = 0.5×50×9.81 =245 N

Since, the applied force is greater than the maximum value of static friction F_s, the object must be in motion. Hence, kinetic friction must be taken into account and not static friction.

By equilibrium condition

ma = F - μ_k m g

where F = 250 N, μ_k = coefficient of kinetic friction = 0.4, m= 50 Kg

a = acceleration of the box

50a = 250-0.4×50×9.81

Solving we get a= 1.08 m/s^2

8 0

2 years ago

(science)<br>pls help this is my last question

Anna007 [38]

Answer:

Whats the question

Explanation:

7 0

2 years ago

Read 2 more answers