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klio [65]
3 years ago
8

Mutt and Jeff are running along a path each pushing a cart loaded with rocks. If Mutt's wagon has a mass two times greater than

Jeff's and they want to stay together, arriving at their destination at the same time, what must happen? A) Jeff should slow down so Mutt can catch up. B) Mutt must use half as much force to push his cart. C) Mutt must use twice as much force to push his cart. D) Mutt and Jeff will use the same force, but Mutt will take bigger steps.
Physics
2 answers:
maria [59]3 years ago
5 0

Force is directly proportional to mass according to the second law of Newton, meaning that the greater the mass is, bigger the force should be in order to move the object. In this case, Mutt's wagon has a mass two times greater than Jeff's and they have to be equal. So either Jeff must slow down twice as much or Mutt has to speed up twice as much. The only option we can choose  according to our reasoning is that Mutt must use twice as much force to push his cart, because his mass is two times bigger. According to me the answer is C).

laiz [17]3 years ago
5 0

Answer:

c

Explanation:

Mutt and Jeff are moving at the same speed. Mutt's cart has double the mass of Jeff's so if he is to stay even with Jeff, he must use twice as much force as Jeff. The greater the mass, the greater the force, assuming the speed is kept constant.

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Guys I really need help with these 2 questions , it's for my final plz help asap
mars1129 [50]

Answer:

(1) Initial speed, u=0

    Final speed, v=165.76m/s

    Average speed, v_a_v_g=82.87m/s

(2) Force of gravity, F_g=12.8\times10^1^5N

Explanation:

(1)

Given,

Distance, S=300meter

Time, t=3.62second

It is given that drag racer started at rest.

So Initial speed, u=0

Using Newton's second equation of motion,

S=ut+\frac{1}{2}at^2\\300=0+\frac{a\times3.62^2}{2} \\a=45.79m/s^2

Newton's first equation of motion,

v=u+at\\=0+45.79\times3.62\\=165.76 m/s

So, Final speed, v=165.76m/s

Average speed is defined as totle distance divided by totle time.

v_a_v_g=\frac{S}{t}\\=\frac{300}{3.62} \\=82.87m/s

So, Average speed, v_a_v_g=82.87m/s

(2)

Gravitation: It is the natural phenomenon in which two different bodies attract each other by virtue of their masses.

       According to Newton's law of gravitation, the force of attraction between two bodies is directly proportional to the masses of the bodies and inversely proportional to square of distance between centers of mass of the bodies.

                         F_g\propto\frac{m_1m_2}{r^2} \\F_g=G\frac{m_1m_2}{r^2}where Gis constant of proportionality and known as gravitation constant.

Given,

Mass of Jupiter, m_1=1.9\times10^2^7kg

Mass of Ganymede, m_2=1.48\times10^2^3kg

Distance between their centers of mass, r=1.21\times10^1^2meter

F_g=G\frac{m_1m_2}{r^2}\\=\frac{6.67\times10^-^1^1\times1.9\times10^2^7\times1.48\times10^2^3}{(1.21\times10^1^2)^2} \\=12.8\times10^1^5N

So, Force of gravity, F_g=12.8\times10^1^5N

7 0
3 years ago
Calculate the wavelength (in nm) of light that produces its first minimum at an angle of 21.0° when falling on a single slit of
Cerrena [4.2K]

To solve this problem it is necessary to apply the related concepts to the principle of overlap, specifically to single slit diffraction experiment concept.

Mathematically this can be expressed as:

dsin\theta = m\lambda

Where,

d = Width of the slit

\lambda =Wavelength

\theta = Angle relative to the original direction of the light

m = Any integer which represent the order of the equation (number of repetition of the spectrum)

To solve the problem we need to rearrange the equation and find the wavelength

\lambda = \frac{dsin\theta}{m}

Our values are given as,

d = 1.46\mu m = 1.46*10^{-6}m

\theta = 21\°

m = 1

Replacing in our equation we have,

\lambda = \frac{dsin\theta}{m}

\lambda = \frac{(1.46*10^{-6})sin(21)}{1}

\lambda = 5.232*10^{-7}m

\lambda = 523.2nm

Therefore the wavelength is 523.2nm

7 0
4 years ago
An increase in the atomic number____the atomic radius moving from
olganol [36]

Answer:

to

Explanation:

7 0
3 years ago
Which term describes the amount of charge that passes a point in a circuit<br> each second?
Flura [38]

Answer:

volts

Explanation:

8 0
3 years ago
Read 2 more answers
If a biker starts at rest and accelerates to 15 m/s in 7.5 seconds, what is his<br> acceleration? *
sergeinik [125]

Answer:

2 m/s^2

Explanation:

from the question

v=15 m/s

t=7.5

a=?

from the first equation of motion

v=u+at

where,

v=final velocity

u=initial velocity

a=acceleration

t=time

from the question (u) will be zero because the body started at rest

v=u+at

15=(0)+a×7.5

15=7.5a

a=15/7.5

a=2 m/s^2

6 0
3 years ago
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