Question

A motorcycle passes over the top of a hill that has a radius of curvature of 100 m. The mass of the motorcycle plus rider is 300 kg. The motorcycle is moving at a speed of 30 m/s. The surface exerts a normal force of magnitude FN on the motorcycle.The motorcycle passes over the top of the hill again but now is moving at a speed of 33 m/s. How does the new normal force exerted on the motorcycle compare to FN

Answer 1

Answer:

$F_N>F_N'$

Explanation:

From the question we are told that

Radius of curvature$r=100m$

Mass $M=300kg$

initial Speed of Motorcycle  $V_1=30m/s$

Final  Speed of Motorcycle  $V_2=33m/s$

Generally the equation Force at initial speed is  mathematically given as

$F_N=mg-\frac{mv^2}{R}$

$F_N=300*9.8-\frac{(300*30)^2}{100}$

$F_N=240N$

Generally the equation Force at Final speed is  mathematically given as

$F_N'=mg-\frac{mv'^2}{R}$

$F_N'=300*9.8-\frac{(300*33)^2}{100}$

$F_N'=-327N$

Therefore

$F_N>F_N'$