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Tems11 [23]
3 years ago
9

Which of the following has helped preserve resources while cutting the demand for energy?

Chemistry
2 answers:
sweet [91]3 years ago
4 0
A is the correct answer
Mekhanik [1.2K]3 years ago
3 0

Answer: Option (D) is the correct answer.

Explanation:

When there is minimum use of energy and we are still able to preserve resources then it means we are cutting the demand for energy.

Therefore, when we are treating water with chlorine then it means without any electricity or energy we are cleaning the water. But at the same time chlorinated water is harmful to use unless chlorine is dissolved in limiting quantity.

Whereas energy efficient appliances will use the electricity efficiently.

Landfill will require the use of machines or man power therefore, energy will be used.

On the other hand, when rules are framed against the use of chlorofluorocarbons then there will be lesser depletion of ozone layer. Hence, use of energy will be minimum.

Thus, we can conclude that legislation against the use of chlorofluorocarbons has helped preserve resources while cutting the demand for energy.

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How many moles are in 64 grams of methane, CH4?<br> A. 4<br> B. 32<br> C. 64<br> D. 13
ss7ja [257]

Answer:

A. 4.

Explanation:

  • We can use the relation:

<em>no. of moles (n) = mass/molar mass.</em>

mass = 64.0 g, molar mass = 16.0 g/mol.

∴ no. of moles (n) = mass/molar mass = (64.0 g)/(16.0 g/mol) = 4 mol.

8 0
3 years ago
Calculate the net force on the object below.
Anastaziya [24]

Answer:

first we add the same direction. 12N + 32 N=44N .

then we add the forces. 54 up + 44N down= 10N up

8 0
3 years ago
Given w = 0, an endothermic reaction has the following.
tamaranim1 [39]

D) + ΔH and +ΔE

Given this is one of the answer choices

8 0
3 years ago
A gas occupies a 1.5 L container at 25 degrees Celsius and 2.0 atm. If the gas is transferred to a 3.0 L container at the same t
harkovskaia [24]

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

P1V1 =P2V2

P2 = P1 x V1 / V2

P2 = 2.0 x 1.5 / 3

<span>P2 = 1 atm</span>

4 0
3 years ago
Read 2 more answers
Propane gas, C3H8, is sometimes used as a fuel. In order to measure its energy output as a fuel a 1.860 g sample was combined wi
lisov135 [29]

Answer:

The heat of the reaction is 105.308 kJ/mol.

Explanation:

Let the heat released during reaction be q.

Heat gained by water: Q

Mass of water ,m= 1kg = 1000 g

Heat capacity of water ,c= 4.184 J/g°C

Change in temperature = ΔT = 26.061°C - 25.000°C=1.061 °C

Q=mcΔT

Heat gained by bomb calorimeter =Q'

Heat capacity of bomb calorimeter ,C= 4.643 J/g°C

Change in temperature = ΔT'= ΔT= 26.061°C - 25.000°C=1.061 °C

Q'=CΔT'=CΔT

Total heat released during reaction is equal to total heat gained by water and bomb calorimeter.

q= -(Q+Q')

q = -mcΔT - CΔT=-ΔT(mc+C)

q=-1.061^oC(1000 g\times 4.184J/g^oC+4.643 J/^oC )=-4,444.15J=-4.444 kJ

Moles of propane =\frac{1.860 g}{44 g/mol}=0.0422 mol

0.0422 moles of propane on reaction with oxygen releases 4.444 kJ of heat.

The heat of the reaction will be:

\frac{4.444 kJ}{0.0422 mol}=105.308 kJ/mol

3 0
3 years ago
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