Well to solve this problem, we must remember that Oxygen
in ionic form is Oxide O2- (an electric charge of negative 2). Hence the
correct formulas and names taking into account the charge of Oxygen are:
c) Co2O3, cobalt(III) oxide
f) CoO, cobalt(II) oxide
P2 = 54.6 kPa
Explanation:
Given:
V1 = 10.0 L. V2 = 50.0 L
P1 = 273 kPa. P2 = ?
We can use Boyle's law to solve this problem.
P1V1 = P2V2
Solving for P2,
P2 = (V1/V2)P1
= (10.0 L/50.0 L)(273 kPa)
= 54.6 kPa
Answer:
It is MgCl₂ because the total positive charge on Mg is two
Explanation:
The bond between the atoms that makes up the formula unit of the compound is an ionic bond. This bond involves the transfer of electrons between atoms.
Mg is in the second group on the period on the periodic table. It has two valence electrons and would readily lose it to have a stable atomic configuration like those of noble gases. This leaves magnesium with a net positive charge of 2. Each chlorine atom gains one electron to achieve their own octet.
