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Sonbull [250]
3 years ago
13

Questions and Problems 22 When water is heated, the temperature eventually reaches a constant value and forms a plateau on the g

raph. What does the plateau indicate? ​
Chemistry
1 answer:
Softa [21]3 years ago
6 0

Answer:

It indicates phase changes:<em> melting then  later boiling.</em>

Explanation:

On the heating curve of water, the plateau marks phase change transitions.The temperature remains constant during this period.The first phase change is melting of water.The second phase change is boiling of water to gas.

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What are the smallest units of matter?<br> O molecules<br> O atoms<br> O compounds<br> elements
mafiozo [28]

Answer:

atoms

Explanation:

letters yo make 20 words

4 0
3 years ago
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As the water velocity decreases, the size of the particles that the water can transport increases. True or false
tiny-mole [99]
The answer is False.
8 0
3 years ago
Yet a third pair of compounds of manganese and oxygen is 50.48% and 36.81% oxygen respectively. In what small whole number ratio
Mariulka [41]

Answer:

The number ratio is 4:7

Explanation:

Step 1: Data given

Compound 1 has 50.48 % oxygen

Compound 2 has 36.81 % oxygen

Molar mass oxygen = 16 g/mol

Molar mass manganese = 54.94 g/mol

Step 2: Calculate % manganes

Compound 1: 100 - 50.48 = 49.52 %

Compound 2: 100 - 36.81 = 63.19 %

Step 3: Calculate mass

Suppose mass of compounds = 100 grams

Compound 1:

 50.48 % O = 50.48 grams

 49.52 % Mn = 49.52 grams

Compound 2:

36.81 % O = 36.81 grams

63.19 % Mn = 63.19 grams

Step 4: Calculate moles

Compound 1

Moles O = 50.48 grams / 16.0 g/mol = 3.155 moles

Moles Mn = 49.52 grams / 54.94 g/mol = 0.9013 moles

Compound 2

Moles O = 36.81 grams / 16.0 g/mol = 2.301 moles

Moles Mn = 63.19 grams / 54.94 g/mol = 1.150 moles

Step 5: calculate mol ratio

We will divide by the smallest amount of moles

Compound 1

O: 3.155/0.9013 = 3.5

Mn: 0.9013 / 0.9013 = 1

Mn2O7

Compound 2

O: 2.301 / 1.150 = 2

Mn: 1.150 / 1.150 = 1

MnO2

The number ratio is 2:3.5 or 4:7

7 0
3 years ago
How many moles of O2 are contained in 32 grams of O2?
Radda [10]

Answer:

2 moles

Explanation:

In one mole of O2 there are 16 grams. So in 2 moles there are 32 grams

7 0
3 years ago
The reaction between solid white phosphorous and oxygen produces solid tetraphosphorous decaoxide (P4010).
Alchen [17]

Answer:

oxygen is limiting reactant

Explanation:

Given data:

Mass of phosphorus = 25.0 g

Mass of oxygen = 50.0 g

What is limiting reactant ?

Solution:

Chemical equation:

P₄   +  5O₂       →      P₄O₁₀

Number of moles of P₄:

Number of moles = mass/molar mass

Number of moles = 25.0 g/ 123.89 g/mol

Number of moles = 0.20 mol

Number of moles of  O₂:

Number of moles = mass/molar mass

Number of moles = 50.0 g/ 32 g/mol

Number of moles = 1.56 mol

now we will compare the moles of reactants with product:

        P₄          :            P₄O₁₀

         1           :              1

      0.20       :          0.20

      O₂           :         P₄O₁₀

       5            :         1

     1.56         :        1/5×1.56 = 0.312 mol

Less number of moles of product are formed by the oxygen thus it will act as limiting reactant.

8 0
3 years ago
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