Explanation:
High carbon concentration in the deep ocean means increased absorption of carbon to the atmosphere resulting to even greater and harmful amounts of carbon in the atmosphere. Therefore we need to keep a close eye of the deep ocean in the quest to monitor and pump out excess carbon from this part of marine life.
The answer is o<span>rganelles.</span>
Answer:-
Solution:- As is clear from the given Ka value, Cinnamic acid is a weak acid. let's calculate the moles of acid and KOH added to it from their given molarities and mL.
For KOH, 
= 0.002 mol
For Cinnamic acid, 
= 0.003 mol
Acid and base react as:

The reaction takes place in 1:1 mol ratio. Since the moles of acid are in excess, the acid is still remaining when all the kOH is used.
0.002 moles of KOH react with 0.002 moles of Cinnamic acid to form 0.002 moles of potassium cinnamate. Excess moles of Cinnamic acid = 0.003 - 0.002 = 0.001
As the solution have weak acid and it's salt(or we could say conjugate base), it is a buffer solution and the pH of the buffer solution could easily be calculated using Handerson equation:

pKa could be caluted from given Ka value using the formula:
pKa = - log Ka

pKa = 4.44
let's plug in the values in Handerson equation and calculate the pH:

pH = 4.44+0.30
pH = 4.74
So, the first choice is correct, pH is 4.74.
Just use q=mCDeltaT
q=energy
m=mass
c=specific heat
Delta T= Change in temperature
Answer: 5.18
Explanation:
Mathematically, pOH is expressed as
pH = -log(OH-)
where OH-is the concentration of hydroxide ion
So, pOH calculations are as follows
pOH = -log(1.50x10-9 M)
pOH = -(-8.82)
pOH = 8.82 [the two minus signs cancelled out]
Since pOH = 8.82; apply the formula
pH + pOH = 14 to get pH of the solution
Hence, pH + pOH = 14
pH + 8.82 = 14
pH = 14 - 8.82
pH = 5.18
Thus, the pH of a solution with a 1.50x10-9 M hydroxide ion concentration is 5.18 (slightly acidic)