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Answer: a= 4.4ms-2
Displacement= 26.95 m
Explanation:
First, the speed in km/hr must be converted to m/s so that we can apply it in solving the question. The motion started from rest hence the initial velocity is 0m/s. The average displacement is also obtained from the equations of motion as shown in the image attached.
Answer:
the average speed in annual work out is 46.5
Answer:
Part a)

Part b)

Part c)

Explanation:
Part a)
As we know that initially the grass hopper is at rest at the ground position
Now the acceleration is given as

distance of the legs that it stretched is given as

so we have



Part b)
time taken to reach this speed is given as



Part c)
as the grass hopper reach the maximum height its final speed would be zero
so we will have



8.0-3.0=5.0metres in the x direction
7.0-5.0=2.0 metres in the y direction
Use Pythagoras
25+4=29
![\sqrt[2]{29 }](https://tex.z-dn.net/?f=%20%5Csqrt%5B2%5D%7B29%20%20%7D%20)
=5.39metres in 2secs
=2.645m/s at an angle of 68.2 degrees to horizontal.... see below!
tan-1 angle = 5/2
angle=68.2 degrees