The value of Kc for the equilibrium is 0.150 mole² / litre ²
<u>Explanation:</u>
<u>Given:</u>
An equilibrium mixture in an 1.00 L vessel contains 5.30 moles of
Mg(OH )₂ 0.800 moles of Mg²⁺ and 0.0010 moles OH₋
We have to find the value of Kc
- Step 1: Find the equilibrium Concentration.
- Step 2: Substitute the values in the equation.
- Step 3: Find the value of Kc.
- I have attached the document for the detailed explanation
The value of Kc for the equilibrium is 0.150 mole² / litre ²
Answer:
The main purpose of the expedition was to conduct a hydrographic survey of the coasts of the southern part of South America.
Answer:
Keq = [CO₂]/[O₂]
Explanation:
Step 1: Write the balanced equation for the reaction at equilibrium
C(s) + O₂(g) ⇄ CO₂(g)
Step 2: Write the expression for the equilibrium constant (Keq)
The equilibrium constant is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It only includes gases and aqueous species. The equilibrium constant for the given system is:
Keq = [CO₂]/[O₂]
Answer:
20.4081633 or 20.408
Explanation:
These ones you can do the regular method but it takes to long just divide and shoot.Hope this helps.
... Really wanna go sleep
