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skad [1K]
3 years ago
11

Oxidation no of carbon in C3H7OH​

Chemistry
1 answer:
mestny [16]3 years ago
6 0

Answer:

-2

Explanation:

7 x 1 - 2 x 1 + 1 x 1 + 3C = 0 (no charge)

6 + 3C = 0

C = -2

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Ede4ka [16]

Answer:

\boxed {\boxed {\sf About \ 1.5 * 10^{24} \ atoms \ Si}}

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First, we must set up Avogadro's number as a ratio.

\frac {6.022 \ * 10^{23} \ atoms \ Si }{1 \ mol \ Si}}

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2.5 \ mol \ Si *\frac {6.022 \ * 10^{23} \ atoms \ Si }{1 \ mol \ Si}}

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2.5 * \frac {6.022 \ * 10^{23} \ atoms \ Si }{1}}

Since the denominator of the fraction is 1, we can cancel it out too.

2.5 *  {6.022 \ * 10^{23} \ atoms \ Si }

1.5055 * 10^{24} \ atoms \ Si

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The 0 in the hundredth place tells us to leave the 5 in the tenth place.

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