<em><u>The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:</u></em>
<em><u>Solution:</u></em>
<em><u>The object falls, its distance, d, above the ground after t seconds, is given by the formula:</u></em>
To find the time interval in which the object is at a height greater than 300 ft
Frame a inequality,
Solve the inequality
Subtract 1000 from both sides
Time cannot be negative
Therefore,
t < 6.61
And the inequality used is:
Step-by-step explanation:
10-5y=3x
1. add 10 to both sides
-5y=3x+10
2. divide everything by -5
y=-3/5x-2
3. your point would start at -2 on the y axis and you would go down 3 and over 5 to get to the next point
Answer:
Kay's husband drove at a speed of 50 mph
Step-by-step explanation:
This is a problem of simple motion.
First of all we must calculate how far Kay traveled to her job, and then estimate the speed with which her husband traveled later.
d=vt
v=45 mph
t= 20 minutes/60 min/hour = 0.333 h (to be consistent with the units)
d= 45mph*0.333h= 15 miles
If Kay took 20 minutes to get to work and her husband left home two minutes after her and they both arrived at the same time, it means he took 18 minutes to travel the same distance.
To calculate the speed with which Kate's husband made the tour, we will use the same initial formula and isolate the value of "V"
d=vt; so
v=
d= 15 miles
t= 18 minutes/60 min/hour = 0.30 h (to be consistent with the units)
v=
Kay's husband drove at a speed of 50 mph
Answer:
-4
Step-by-step explanation:
-3r+9=-4r+5
-3r+4r=5-9
r=-4
Answer:
So, 13 - 20 ÷2 + 10 = 13 - 10 + 10 = 3 + 10 = 13 ;
Step-by-step explanation: