Answer:
1) 50 seconds 2) 100°C
Explanation:
(Follows formula of Power=Energy/Time)
1) 500W x X = 2000J/kg°C x .25kg x 50°C
X = 50 seconds.
2) 2000W x 300s = 1000J/kg°C x 2kg x X
X = 300
Initial temperature => 400°C-300°C = 100°C
Suppose rowing speed is V km/s.
So, upstream speed = V-2
Downstream speed = V+ 2
Total time is taken 3 h 20 min to cover up and down journey of 5 km.
So, total time = upstream time + downstream time
and 
, we take only positive velocity.
Thus, the the rowing speed of the crew in still water is 1 km/s.
The answer is 12 J
because you have to multiply the two together. hope it helps
Answer:
a) time taken = 2.66 s
b) v = 28.34
Explanation:
given,
rate of descending = 2.3 m/s
height of camera above ground = 41 m
using equation of motion
4.9 t² + 2.3 t - 41 =0
t = 2.66 ,-3.13
time taken = 2.66 s
b) v² = u² + 2 g h
v² = 0 + 2× 9.8 × 41
v = 28.34
Below is the answer:
W = mg
<span>W = ? </span>
<span>m = 670 </span>
<span>g = ? </span>
<span>radius of Neutron star = 11.5 km = 11,500 meters </span>
<span>We need to find g on the Neutron star, so: </span>
<span>g = GM/r^2 </span>
<span>g = 6.67 x 10^-11 x 1.99 x 10^30/11,500^2 </span>
<span>g = 1 x 10^12 </span>
<span>W = 670 x (1 x 10^12) </span>
<span>W = 6.7 x 10^14 N
</span>
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