Answer:
24 m/s
Explanation:
Given that,
A typical road bike wheel has a diameter of 70 cm including the tire.
Speed of the cyclist = 12 m/s
We need to find the speed at the top of the tire moving. The velocity of the topmost point is twice that of the velocity of the object.
v = 2 × 12
= 24 m/s
Hence, the required velocity is 24 m/s.
Answer:
1178 nm
Explanation:
We are given that
Wavelength of light=![\lambda=589nm=589\times 10^{-9} m](https://tex.z-dn.net/?f=%5Clambda%3D589nm%3D589%5Ctimes%2010%5E%7B-9%7D%20m)
![1nm=10^{-9} m](https://tex.z-dn.net/?f=1nm%3D10%5E%7B-9%7D%20m)
We have to find the thickness of spacer if five dark fringes are observed between the edges of the glass.
Suppose that first dark fringe and fifth dark fringe near spacer, then the path length of light is 4 times the wavelength of light.
The light passes through air film is two times then the change in air film thickness from one edge to other is two times the wavelength of light.
Change in air film thickness from one edge to other edge is same as the thickness of spacer.
Therefore, thickness of spacer=![2\lambda](https://tex.z-dn.net/?f=2%5Clambda)
Thickness of spacer=
m
Thickness of spacer=1178 nm
Hence, the thickness of spacer=1178 nm
Answer:
D. The circulatory system transports oxygen that the respiratory system brings into the body.
Explanation:
the first two answers either refer to carbon dioxide as beneficial and necessary to the body(it sometimes is but not in this case)
the answer choice c refers to oxygen being transferred directly to the heart. This is also incorrect.
the only proper answer to this question is answer choice d.
Answer: a) r= 4.82 * 10^-4 m ; b) 1420 V
Explanation: In order to solve this problem we have to take into account that potential for a sphere respec to V=0 at the infinity, which is given by:
V=k*Q/r where r is the radius of the drop
then we have
r=k*Q/V=9*10^9*38pC/710V= 4.82 * 10^-4 m
Finally if we join two drop to form one with the same radius but with twice charge the resultant potential is:
V= k*2*Q/(r)= 710*2= 1420 V
The properties of magma that determines the intensity or nature of volcanic eruptions are: (1) <em>viscosity</em>, (2)<em> temperature</em>, and (3) the <em>amount of dissolved gases</em>. Viscosity describes the flowability of a fluid and its resistance to flow. Magma with low viscosity are more fluid-like and lets gases escape.