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Radda [10]
3 years ago
12

Neutron stars, such as the one at the center of the Crab Nebula, have about the same mass as our sun, but a much smaller diamete

r.
If you weigh 670 on the earth, what would you weigh on the surface of a neutron star that has the same mass as our sun and a diameter of 20.0 ?
Physics
1 answer:
MAVERICK [17]3 years ago
3 0
Below is the answer:

W = mg 

<span>W = ? </span>
<span>m = 670 </span>
<span>g = ? </span>

<span>radius of Neutron star = 11.5 km = 11,500 meters </span>

<span>We need to find g on the Neutron star, so: </span>
<span>g = GM/r^2 </span>
<span>g = 6.67 x 10^-11 x 1.99 x 10^30/11,500^2 </span>
<span>g = 1 x 10^12 </span>

<span>W = 670 x (1 x 10^12) </span>
<span>W = 6.7 x 10^14 N
</span>
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

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Friction always acts____ and in the ____ direction of the motion of an object ​
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Answer:

Friction force always acts tangent to the surface at points of contact. Friction force acts opposite to the direction of motion. There are 2 types of friction: Static friction: If the two surfaces in contact do not move relative to each other, one has static friction.

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Find :
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Answer:

Explanation:

b) Gravity reduces the initial upward velocity to zero in a time of

t = v/g = 40/10 = 4 s

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8 0
2 years ago
Albert presses a book against a wall with his hand. As Albert gets tired, he exerts less force, but the book remains in the same
marissa [1.9K]

Answer:

maximum static frictional force of the wall on the book (Increasing)

normal force of the wall on the book (Decreasing)

weight of the book (Not changing)

Explanation:

Now according to Newton's third law of motion

"Every action has equal but opposite reaction"

By the data given in question, Albert was pressing the book against the wall.Now, Albert started to reduce his force up against the wall.

First we have to consider all the forces applied on book in this scenario.

1. Weight of book acting downwards (y-axis)

2. Friction between book and wall acting upward (y-axis)

3. Albert's force on book against wall (x-axis)

4. Normal reaction of wall against Albert's force (x-axis)

Now, when Albert reduced his force, new scenario will be

1. Weight will be remain constant as it is W = mg

Neither mass nor acceleration due to gravity changed, so weight acting upon the book will remain same.

2. When Albert reduced force, normal reaction of wall reduced against it according to Newton's third law of motion

3. Now notice that friction is a force which acts in accordance with the applied force. For example if a box is placed at floor, no friction is applied, but when you drag the box, friction starts to act and increases until its limit comes. So, when Albert reduced his force, weight will try to pull the book and maximum static friction will increase to hinder the movement of book downwards.

Notice that maximum static friction will hinder the book from movement, since Albert reduced his force, but wight didn't pull the book, which means that maximum static friction increased to hinder downward motion.

7 0
3 years ago
A force of 55N accelerates a 7.5kg wagon at 5.3 m/s^2 along a road. How large is the frictional force?
Varvara68 [4.7K]

Answer:

<h2>15.25 N</h2>

Explanation:

       A force of 55\text{ }N is acting on a wagon along the road. The wagon weights 7.5\text{ }kg. Acceleration of the wagon is given as 5.3\text{ }\frac{m}{s^{2}}.

       Consider the block as the system, the forces acting are Frictional force, Gravitational force, Normal reaction and External force applied by us.

       Gravitational Force and Normal Reaction cancel out each other.

       Net External Force = Mass of system/wagon \times Acceleration of wagon

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4 0
3 years ago
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Answer:

d) 0 V

Explanation:

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By symmetry, all four charges are at the same distance from the center, so we can write the total potential, as follows:

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where d, is the semi-diagonal of the square, that we can find applying Pythagorean theorem, as follows:

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which is equal to the option d).

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3 years ago
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