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4 years ago

For the equation -4y=8x, what is the constant of variation?

Mathematics

1 answer:

alina1380 [7]4 years ago

6 0

Answer:

Step-by-step explanation:

In a normal equation, y=mx+b, the constant of variation is the thing that "constantly" "varies" and in other words changes the same. This is the slope. In the equation, the slope is m.

-4y=8x

y=-2x

The constant of variation, aka slope, is -2

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Write thevfraction as a mixed number 31/6

Alex787 [66]

The fraction 31/6 as a mixed number would be 5 1/6 because 6 goes into 31 5 times and you have 1 left over! So it would be 5 1/6. Hope that helps!

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3 years ago

Read 2 more answers

5. |4| = _____ 6. |-2 1/2| = _____ 7. |-8.673| = _____ 8. |-1,834| = _____

MatroZZZ [7]

Answer:

The absolute value is the distance between a number and zero. The distance between −7 - 7 and 0 0 is 7 7 . 7 7. |−7| | - 7 | ...

Step-by-step explanation:

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3 years ago

Arandom sample of n1 =12 students majoring in accounting in a college of business has a mean grade-point average of 2.70 (where

antiseptic1488 [7]

Answer:

We accept the null hypothesis that the mean gpa's are equal, with the 5 percent level of significance.

Step-by-step explanation:

We have these following hypothesis:

Null

Equal means

$\mu_{1} = \mu_{2}$

Alternative

Different means

$\mu_{1} \neq \mu_{2}$

Our test statistic is:

$\frac{\overline{Y_{1}} - \overline{Y_{2}}}{\sqrt{\frac{s_{1}^{2}}{N_{1}} + \frac{s_{2}^{2}}{N_{2}}}}$

In which $\overline{Y_{1}}, \overline{Y_{2}}$ are the sample means, $N_{1}, N_{2}$ are the sample sizes and $s_{1}, s_{2}$ are the standard deviations of the sample.

In this problem, we have that:

$\overline{Y_{1}} = 2.7, s_{1} = 0.4, N_{1} = 12, \overline{Y_{2}} = 2.9, s_{2} = 0.3, N_{2} = 10$

$T = \frac{2.7 - 2.9}{\sqrt{\frac{0.4}^{2}{12} + \frac{0.3}^{2}{10}}} = -1.3383$

What to do with the null hypothesis?

We will reject the null hypothesis, that is, that the means are equal, with a significante level of $\alpha$ if

$|T| > t_{1-\frac{\alpha}{2},v}$

In which v is the number of degrees of freedom, given by

$v = \frac{(\frac{s_{1}^{2}}{N_{1}} + \frac{s_{2}^{2}}{N_{2}})^{2}}{\frac{\frac{s_{1}^{2}}{N_{1}}}{N_{1}-1} + \frac{\frac{s_{2}^{2}}{N_{2}}}{N_{2} - 1}}$

Applying the formula in this problem, we have that:

$v = 20$

So, applying t at the t-table at a level of 0.975, with 20 degrees of freedom, we find that

$t = 2.086$

We have that

$|T| = 1.3383$

Which is lesser than t.

So we accept the null hypothesis that the mean gpa's are equal, with the 5 percent level of significance.

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3 years ago

For which distributions is the median the best measure of center? Select each correct answer. Y 20 30 18 25 16 20 14 15+ 12 10+

AURORKA [14]

Answer:

The median is the best measure of center for distributions C and D.

Step-by-step explanation:

The median is the best measure of center for skewed distributions or distributions with outliers because it is a robust statistic, meaning that outliers and skewed data have little effect on the median.

Meanwhile, the mean is a good measure of center for symmetric distributions since it is non-robust.

Answer A has a roughly symmetric distribution, and answer B has a uniform distribution.

Answer C has a left-skewed distribution, and answer D seems to have a right-skewed distribution (since the right tail is longer than the left tail).

Therefore, the median would be the best measure of center for choices C and D.

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3 years ago

Please help, Will mark BRAINLIEST, 20 POINTS!

Anestetic [448]

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3 years ago