The exact molecular mass for butane (C4H10) is
12.0096*4+1.0079*10=58.1174 which is 58.1 to 3 significant figures.
Proportion of carbon in the compound
12.0096*4: 58.1174
=>
48.0384 : 58.1174
The mass of carbon in 2.50 grams of butane can be obtained by proportion, namely
Mass of carbon
= 2.50 * (48.0384/58.1174)
= 2.0664
= 2.07 g (approximated to 3 significant figures)
PbO2 (s) + 4 HCl (aq) → PbCl2 (s) + Cl2 (g) + 2 H2O (l)
This is an oxidation-reduction (redox) reaction:
PbIV + 2 e- → PbII
(reduction)
2 Cl-I - 2 e- → 2 Cl0
(oxidation)
PbO2 is an oxidizing agent, HCl is a reducing agent.
Neither a raindrop is a liquid just like water
“Is a percentage of atoms with a specific atomic mass found in a naturally occurring sample of an element.” < you can try and put it in your own words or you could stick with that just add quotations :)
It’s is c, if you oook it’s the only clear answer