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Serggg [28]
3 years ago
8

Given 9.0 moles of O2, how many grams of H2O can be produced ?

Chemistry
1 answer:
Anastasy [175]3 years ago
5 0

Answer:

If we have one mole of water, then we know that it will have a mass of 2 grams (for 2 moles of H atoms) + 16 grams (for one mole O atom) = 18 grams.

Explanation:

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How many molecules (or formula units) are in 138.56 g C4H10 Express your answer using four significant figures.
Semenov [28]

Answer:

dont buy cheap and off we went

7 0
3 years ago
Colligative property definition chemistry
Vadim26 [7]

Answer: Colligative properties are those properties of solutions that are dependent on the concentration of the solutes in the solution.

Colligative properties has to do with solutions, that is, solutes that are dissolved in solvents. Examples of colligative properties are: freezing point depression, vapour pressure lowering, boiling point elevation and osmotic pressure. Colligative properties do not depend on the identity of the solutes, this implies that the effect of colligative properties are uniform across all solutions. For example, the freezing point depression of any solution will depend on the concentration of solutes that are dissolve in solution.

4 0
3 years ago
Carbon monoxide (CO) reacts with hydrogen (H2) to form methane (CH4) and water (H2O).
Artemon [7]

Answer:

5.9x10^-2 M

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Concentration of CO, [CO] = 0.30 M

Concentration of H2, [H2] = 0.10 M

Concentration of H2O, [H2O] = 0.020 M

Equilibrium constant, K = 3.90

Concentration of CH4, [CH4] =..?

Step 2:

The balanced equation for the reaction. This is given below:

CO(g) + 3H2(g) <=> CH4(g) + H2O(g)

Step 3:

Determination of the concentration of CH4.

The expression for equilibrium constant of the above equation is given below:

K = [CH4] [H2O] / [CO] [H2]^3

3.9 = [CH4] x 0.02/ 0.3 x (0.1)^3

Cross multiply to express in linear form

[CH4] x 0.02= 3.9 x 0.3 x (0.1)^3

Divide both side by 0.02

[CH4] = 3.9 x 0.3 x (0.1)^3 /0.02

[CH4] = 5.9x10^-2 M

Therefore, the equilibrium concentration of CH4 is 5.9x10^-2 M

5 0
3 years ago
Help me pls its chemistry
saul85 [17]

B to C:-

  • The temperature remains constant from B to C in any time interval .
  • Looking at the graph there is BC || x axis.
  • Hence temperature remains unchanged.

E to D:-

  • Here also the temperature remains constant.
  • As we can see ED|| x axis
8 0
2 years ago
Describe in general terms the structure of ionic solids such as nacl
allochka39001 [22]
<span>Ionic compounds are chemical compounds in which ions are held together in a lattice structure by ionic bonds. They have a high melting and boiling point, and they have a high hardness and are very brittle. The cations and anions are stuck together in a sense. So in this case, sodium (Na) is attracted to Chlorine (Cl).</span>
8 0
3 years ago
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