The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How
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128 ml is the voume of the balloon if the temperature of the gas increases to 320.0k.
Explanation:
given that:
T1 (initial temperature) = 300K
V1 ( initial volume) = 120ml
T2 (final temperature) = 320 K
V2 (final volume) = ?
Pressure remained constant throughout the process.
From the equation
=
Since pressure is constant the equation will be:
=
V2 =
Putting the values in the above formula:
V2 =
= 128 ml
128 ml is the volume of the gas if temperature increases from 3OO K to 320k