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4 years ago

Consider the two groups listed below. Which statement describes the sets?

1 answer:

6 0

The correct answer is: 
D) neither the relation (length, volume) nor the relation (volume, length) is a function.

Explanation: 
A function is a relation in which each element of the domain is mapped to no more than 1 element of the range.
For (length, volume), the domain would be length and the range would be volume.
There could possibly be a length value that is mapped to more than one volume value, depending on the height of the pool. This means that (length, volume) is not always a function.
For (volume, length), volume is the domain and length is the range.
There could possibly be a volume that is mapped to more than one length, depending on the height of the pool. This means that (volume, length) is not always a function either.

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Which equation represents a line that passes through 4 6) and is parallel to the line whose equation is 3x - 4y= 6

Pachacha [2.7K]

Parallel means their slopes should equal to each other.

Thus we need to find the slope of the given line ,

Let's do it.....

$3x - 4y = 6$

Subtract sides -3x

$- 3x + 3x - 4y = - 3x + 6$

$- 4y = - 3x + 6$

Divided sides by -4

$\frac{ - 4}{ - 4}y = \frac{ - 3}{ - 4}x + \frac{6}{ - 4} \\$

$y = \frac{3}{4}x - \frac{3}{2} \\$

This is the slope-intercept of the line.

We know that the coefficient of the x in slope-intercept form , is the slope of the line.

Thus the slope of the equation which we want is :

$slope = \frac{3}{4} \\$

_________________________________

We have following equation to find the point-slope form of the linear functions.

$y - y(given \: point) = slope \times (x - x(g \: p) \: ) \\$

Now just need to put the slope and the given point in the above equation.

$y - 6 = \frac{3}{4} \times (x - 4) \\$

Multiply sides by 4

$4(y - 6) = 3(x - 4)$

$4y - 24 = 3x - 12$

Plus sides 24

$4y - 24 + 24 = 3x - 12 + 24$

$4y = 3x + 12$

Subtract sides -3x

$4y - 3x = 3x - 3x + 12$

$4y - 3x = 12$

And we're done....♥️♥️♥️♥️♥️

4 0

3 years ago

Please solve this simultaneous equation, i'm not that good at it. 2r-s=10 rs-s^2=12

o-na [289]

Answer:

s = 6, r = 8 or s = 4, r = 7

Step-by-step explanation:

2r - s = 10

2r = 10 + s

r = 5 + s/2 --(1)

rs - s^2 = 12 --(2)

sub (1) into (2):

(5 + s/2)s - s^2 = 12

5s + 0.5s^2 - s^2 = 12

-0.5s^2 + 5s - 12 = 0

s^2 - 10s + 24 = 0

(s - 6)(s - 4) = 0

therefore s = 6 or s = 4

when s = 6, r = 8 and when s = 4, r = 7

if you would like to discover more about simultaneous equations, you can have a look at my Instagram page (learntionary). I'll be posting mathematics related stuff there and some of my notes (simultaneous enq notes are already posted!)

7 0

3 years ago

If 5x-3y=12 and 4x-5y=17 what is the value of y?

il63 [147K]

Answer:

Step-by-step explanation:

3 0

3 years ago

Simplify. –2 • (4) – 3 • (–5) = A. 55 B. 7 C. –23 D. –120

stepan [7]

Your answer to the question is B) 7

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