Examine the ph scale below. How does household bleach compare to household ammonia?
2 answers:
Household bleach compare to household ammonia = D) Household ammonia has 10 times higher H + concentration.
<h3>Further explanation </h3>pH is the acidity level of a solution that depends on the concentration of the H⁺ ion. The greater the value the more acidic the solution and the smaller the pH.
<h3>pH = - log [H⁺] </h3>So that the two quantities between pH and [H⁺] are inversely related because they are associated with negative values.
A solution with a different value of n has a difference of H ion ion concentration of 10ⁿ.
See the attached picture
We can see the pH value of each solution:
Ammonia household pH = 11.5
Household bleach pH = 12.5
From the choices of answers we complete as follows:
A) Household bleach is more acidic than ammonia household.
B) Household bleach has 10 times higher H + concentration than household ammonia.
C) Household bleach has 100 times higher H + concentration than household ammonia.
D) Household ammonia has 10 times higher H + concentration.
E) Household ammonia has 100 times higher H + concentration.
Then both of them have H⁺ ion concentrations of
Ammonia household pH = 11.5
11.5 = - log H⁺
H⁺ =
Household bleach pH = 12.5
12.5 = - log H⁺
H⁺ =
The difference in concentration:
the pH of a solution
Calculate the pH
the pH of a 2.0 M solution of HClO4
Keywords: household ammonia, household bleach, pH
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Given that, an experiment to measure the enthalpy change for the reaction of aqueous copper(II) sulfate, CuSO4(aq) and zinc, Zn(s) was carried out in a coffee cup calorimeter; the heat of the reaction in the whole system is calculated to be 2218.34 kJ
Heat of reaction (i.e enthalpy of reaction) is the quantity of heat that is required to be added or removed when a chemical reaction is taken place in order to maintain all of the compounds present at the same temperature.
The formula used to calculate the heat of the reaction can be expressed as follows:
Q = mcΔT
where:
- Q = quantity of heat transfer
- m = mass
- c = specific heat of water = 4.18 kJ/g °C (constant)
- ΔT = change in temparature
From the information given:
- The initial temperature (T₁) = 25° C
- The final temperature (T₂) = 91.5° C
∴
The change in temperature i.e. ΔT = T₂ - T₁
ΔT = 91.5° C - 25° C
ΔT = 66.5° C
The number of moles of CuSO₄ = 1.00 mol/dm³ × 50.0 cm³
= 0.05 moles
- Since the molar mass of CuSO₄ = 159.609 g/mol
Then;
Using the relation:
By crossing multiplying;
mass of CuSO₄ = number of moles of CuSO₄ × molar mass of CuSO₄
mass of CuSO₄ = 0.05 moles × 159.609 g/moles
mass of CuSO₄ = 7.9805 grams
∴
Using the formula from above:
Q = mcΔT
Q = 7.9805 g × 4.18 kJ/g °C × 66.5° C
Q = 2218.34 kJ
Therefore, we can conclude that the heat of the reaction is 2218.34 kJ
Learn more about the chemical reaction here: