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DENIUS [597]
4 years ago
14

Examine the ph scale below. How does household bleach compare to household ammonia?

Chemistry
2 answers:
Marina86 [1]4 years ago
8 0

Household bleach compare to household ammonia = D) Household ammonia has 10 times higher H + concentration.

<h3>Further explanation </h3>

pH is the acidity level of a solution that depends on the concentration of the H⁺ ion. The greater the value the more acidic the solution and the smaller the pH.

<h3>pH = - log [H⁺] </h3>

So that the two quantities between pH and [H⁺] are inversely related because they are associated with negative values.

A solution with a different value of n has a difference of H ion ion concentration of 10ⁿ.

See the attached picture

We can see the pH value of each solution:

Ammonia household pH = 11.5

Household bleach pH = 12.5

From the choices of answers we complete as follows:

A) Household bleach is more acidic than ammonia household.

B) Household bleach has 10 times higher H + concentration than household ammonia.

 C) Household bleach has 100 times higher H + concentration than household ammonia.

 D) Household ammonia has 10 times higher H + concentration.

 E) Household ammonia has 100 times higher H + concentration.

 

Then both of them have H⁺ ion concentrations of

Ammonia household pH = 11.5

11.5 = - log H⁺

H⁺ = {\displaystyle 10^{-11.5}

Household bleach pH = 12.5

12.5 = - log H⁺

H⁺ =  {\displaystyle 10^{-12.5}

The difference in concentration:

{\displaystyle {\frac{10^{-11.5}}{10^{-12.5}}=10

<h3>Learn more </h3>

the pH of a solution

brainly.com/question/4039716

Calculate the pH

brainly.com/question/9278932

the pH of a 2.0 M solution of HClO4

brainly.com/question/1599662

Keywords: household ammonia, household bleach, pH

Kazeer [188]4 years ago
6 0

Answer is: household ammonia has 10 times higher H⁺ concentration.

1) pH(household ammonia) = 11.5.

pH = -log[H⁺], approximately the negative of the base 10 logarithm of the molar concentration of hydrogen ions.

[H⁺] = 10∧(-pH).

[H⁺] = 10∧(-11.5).

[H⁺] = 3.16·10⁻¹² M; concentration of hydrogen ions.

2) pH(household bleach) = 12.5.

[H⁺] = 10∧(-12.5).

[H⁺] = 3.16·10⁻¹³ M.

3) 3.16·10⁻¹² M / 3.16·10⁻¹³ M = 10.

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A certain substance X has a normal freezing point of -10.1 degree C and a molal freezing point depression constant Kf = 5.32 °C.
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Answer : The freezing point of a solution is -15.4^oC

Explanation : Given,

Molal-freezing-point-depression constant (K_f) = 5.32^oC/m

Mass of urea (solute) = 29.82 g

Mass of solvent = 500 g  = 0.500 kg

Molar mass of urea = 60.06 g/mole

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of urea}}{\text{Molar mass of urea}\times \text{Mass of solvent in Kg}}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution = ?

\Delta T^o = freezing point of solvent = -10.1^oC

i = Van't Hoff factor = 1 (for urea non-electrolyte)

K_f = freezing point constant = 5.32^oC/m

m = molality

Now put all the given values in this formula, we get

-10.1^oC-T_s=1\times (5.32^oC/m)\times \frac{29.82g}{60.06g/mol\times 0.500kg}

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Part 1. Determine the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm. Show your work.
zaharov [31]

If a sample of gas is a 0.622-gram, volume of 2.4 L at 287 K and 0.850 atm. Then the molar mass of the gas is 7.18 g/mol

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases.

An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given :

  • V = 2.4 L = 0.0024
  • P = 86126.25 Pa
  • T =  287 K
  • m = 0.622
  • R = 8.314

The ideal gas equation is given below.

n = PV/RT

n = 86126.25 x 0.0024 / 8.314 x 287

n = 0.622 / molar mass (n = Avogardos number)

Molar mass =  7.18 g

Hence, the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm is 7.18 g

More about the ideal gas equation link is given below.

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