Answer:
319.15^{o}C[/tex]
Explanation:
When all other variables are constant, we are allowed to use the formula
![\frac{T_{2} }{V_{2} } = \frac{T_{1} }{V_{1} } \\Which can be rewritten as T_{2} = \frac{T_{1} V_{2} }{V_{1} }if you make T2 the subject of the formula. This formula is true only if temperature is in Kelvin not degrees Celsius so T1 must be converted to KelvinNow to calculate T2[tex]T_{2}= \frac{296.15K*3.38.10^{3}L }{1.69.10^{3}L }= 592.3K](https://tex.z-dn.net/?f=%5Cfrac%7BT_%7B2%7D%20%7D%7BV_%7B2%7D%20%7D%20%3D%20%5Cfrac%7BT_%7B1%7D%20%7D%7BV_%7B1%7D%20%7D%20%5C%5C%3C%2Fp%3E%3Cp%3EWhich%20can%20be%20rewritten%20as%20T_%7B2%7D%20%3D%20%5Cfrac%7BT_%7B1%7D%20V_%7B2%7D%20%7D%7BV_%7B1%7D%20%7D%3C%2Fp%3E%3Cp%3Eif%20you%20make%20T2%20the%20subject%20of%20the%20formula.%20This%20formula%20is%20true%20only%20if%20temperature%20is%20in%20Kelvin%20not%20degrees%20Celsius%20so%20T1%20must%20be%20converted%20to%20Kelvin%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3ENow%20to%20calculate%20T2%3C%2Fp%3E%3Cp%3E%5Btex%5DT_%7B2%7D%3D%20%5Cfrac%7B296.15K%2A3.38.10%5E%7B3%7DL%20%7D%7B1.69.10%5E%7B3%7DL%20%7D%3D%20592.3K)
= 
Pretty sure it's b but not an definitely
Answer:
pH = 2
A 0.010 M solution of hydrochloric acid, HCl, has a molarity of 0.010 M. This means that [H+] = 1 x 10-2 M. The pH of this aqueous solution of H+ ions is pH = 2
hope this helps :3
Answer:
The new substance will need more energy to form its chemical bonds than the old substance will release. ... More energy will be released from the old substance than the new substance will need to form its chemical bonds.
Explanation:
This is the answer I got. Hope it's really helpful
Assuming It is Iron (II)
Na2CO3 + Fe(CLO2) --> FeCO3 + Na2(CLO2)
FeCO3 forms a precipitate in aqueous solution
(2Na+) + (Fe2+) + (CLO2(2-)) + (CO3(2-)) --> FeCO3 + (2Na+) + (CLO2)(2-))
Sodium and Chlorite ions become spectator ions as they do not form precipitates on both sides of equations
(Fe2+) + (CO3(2-)) --> FeCO3
