Answer:
Yes, result is significant ; PVALUE < α
Step-by-step explanation:
Given :
x = 536
n = sample size = 1012
Phat = x / n = 536 / 1012 = 0.5296 = 0.53
H0 : P0 = 0.5
H1 : P0 > 0.5
Test statistic :
(Phat - P0) ÷ sqrt[(P0(1 - P0)) / n]
1-P0 = 1 - 0.5 = 0.5
(0.53 - 0.5) ÷ sqrt[(0.5*0.5)/1012]
0.03 ÷ 0.0157173
= 1.9087
Pvalue :
Using the Pvalue from test statistic :
Pvalue = 0.02815
To test if result is significant :
α = 0.05
0.02815 < 0.05
Pvalue < α ; Hence, result is significant at α=0.05; Hence, we reject H0.
4/5 = 80%
2/3 = 66.66666...%
4/5 is a bigger fraction, so (4/5) x 45 is a bigger fraction.
Remember, -(-x)=x because the negatives cancel out
so
when p=-6 and q=7
p+(-q)-3
-6+(-7)-3
-6-7-3
-13-3
-16
1. We know that 30% expressed as a decimal is 0.30
Since 30% of people were using the internet, 0.30*3200 is our answer.
3200*0.30= 960.
Therefore 960 people were using the internet out of the 3200 surveyed.
Step-by-step explanation:
8.
Prime factorization of 48 is :
Option (3) is true.
9.
Prime factorization of 19 is:
19 = 19 × 1
Option (c) is correct.
(10).
Prime factorization of 924 is:
924 = 2 x 2 x 3 x 7 x 11
= 2² x 3¹ x 7¹ x 11¹
Hence, this is the required solution.
