Now, balance the equation:
in gaseous state exist as a diatomic molecule.
"C6H12O6 and HC2H3O2" is the one pair among the following choices given in the question in which both <span>compounds have the same empirical formula. The correct option among all the options that are given in the question is the fourth option or option "D". I hope the answer has come to your great help.</span>
Answer:
This is a double displacement reaction, C goes with Cl in the products side and O2 goes with H. All that is left is to balance the equation, making sure each side has equal amounts of atoms.
d G = 2 (dG NOCl) - 2 (dG NO)
= 2 * 66.08 - 2 * 87.6 = -43.04 kJ /mol
dG = - 2.303 RT log K
-43.04 = - 2.303 RT log K
7.54 = log K
K = 3.42 * 10^7
Kp = k (RT)^dn
d n = 2 - 1 -2 = -1
Kp = (3.42 * 10^7) (8.314 * 298)^-1
Kp = 1.31 * 10^4
F.
it's the greatest electron "hogger"
as you get closet to it, the stronger the electro negitivity.
He is halogen : they don't like to gain electrons. they are already stable.
Fr and Rn
are metals as far is I can remember. they would prefer losing electrons.
