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4 years ago

ANSWER QUICK PLSSSSSS!!!!!!!! Brainliest for the best answers

Physics

2 answers:

ale4655 [162]4 years ago

8 0

1. Absorbs blue, violet and red spectrums, reflects green rays.

2. The coverage of the green spectrum, to see more green tones.

3. Electromagnetic waves such as light do not interfere with each other’s path, it is one of the basic rules.

4. See 3.

5. Between red and violet.

6. Human eyes adapted to see in the light, as we don’t live underwater and have no need to see at night.

7. The only thing that changes between them is the frequency, both are electromagnetic.

8. Heat.

9. Heat.

10. All electromagnetic.

11. The more dense, the less it refracts.

12. Going through different densities.

13. Refraction.

14. Real, inverted and smaller. Between F and C.

15. Real, inverted and bigger. Before C.

16. Range of colors dispersed by white light. First used for the rainbow.

17. Reflection.

That was long, hope you get it!

Anna007 [38]4 years ago

5 0

Answer:

Explanation:

1. Wavelengths in blue and red spectrum are absorbed in greater quantity

while more yellow , orange and green are reflected in greater quantity giving the leaves their characteristic green color.

2. The Rod Cells increase our ability to see at night thru the use of Rhodopsin also known as visual purple- a light sensitive protein that activates the rod cells and permits one to see at night.

3. The superposition of two light waves with one another such that the crest one light wave fall on another crest and the trough of one light wave falls on another trough, the resultant light wave has a larger amplitude is a called a constructive interference.

4. When the superposition of two light waves with one another such that the crest of one light wave fall on another crest and the trough of one light wave fall on another the resultant amplitude is decreased or even destroyed is called destructive interference.

5. The visible light spectrum part of the electromagnetic spectrum and divided into seven colors such as red orange green yellow blue indigo and violet with wavelength from long to short that is 740 nm to 435 nm.

6. The true statement is that the violet color of the visible light spectrum part of the electromagnetic spectrum has the strongest energy than all other colors.

7. Radio waves and microwaves are two types of electromagnetic waves, the former is used in communication field and latter is used in industries and astronomy both have long wavelength and have lowest frequency and radiant energy.

8. The infrared region is invisible to the human eyes but it is felt as heat and seen with the aid of thermogram.

9. Humans recognize the infra red spectrum because of the heat.

10. Infrared radiation

11. They are closely related when subjected to pressure the density will rise and so its refractive index and when density falls its refractive index falls too.

12. A prism

13. A prism separates white light into colors of visible spectrum and as it passes thru the prism shorter wavelength refracts than longer wave lengths and the rainbow colors separate.

14. The image formed is real, inverted and reduced.

15. The image formed is real, inverted and enlarged.

16. Spectrum is a Latin word for apparition (Image/appearance)

17. Reflexio is the Latin root for reflection.

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A bicycle wheel with radius 0.3 m rotates from rest to 3 rev/s in 5 s. What is the magnitude and direction of the total accelera

AlekseyPX

Answer:

Explanation:

Given

Radius of bicycle wheel $r=0.3\ m$

Initial angular velocity $\omega _0=0$

It rotates 3 revolution in 5 s therefore

$\omega =2\pi 3=\6\pi =18.85\ rad/s$

using $\omega =\omega _0+\alpha t$

where $\alpha =angular\ acceleration$

$\omega =Final\ angular\ velocity$

$t=time$

$\alpha =\frac{18.85}{5}=3.77 rad/s^2$

Total acceleration of any point will be a vector sum of tangential acceleration and centripetal acceleration

$\omega at t=1$

$\omega =0+3.77\times 1=3.77 rad/s$

$a_c=\omega ^2\cdot r$

$a_c=(3.77)^2\cdot 0.3=4.26 m/s^2$

Tangential acceleration $a_t=\alpha \times r$

$a_t=3.77\times 0.3=1.13 m/s^2$

$a_{net}=\sqrt{a_t^2+a_c^2}$

$a_{net}=\sqrt{(1.13)^2+(4.26)^2}$

$a_{net}=4.41 m/s^2$

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4 years ago

When a carpenter shuts off his circular saw, the 10.0 inch diameter blade slows from 4250 rpm to 0.00 in 4.00 s. (a) What is the

MaRussiya [10]

Answer:

(a) $\alpha=-111.26rad/s$

(b) $s=4450.6in$

Explanation:

First change the units of the velocity, using these equivalents $1rev=2\pi rad$ and $1 min =60s$

$4250rpm(\frac{2\pi rad}{1rev})(\frac{1 min}{60 s} )=445.06rad/s$

The angular acceleration $\alpha$ the time rate of change of the angular speed $\omega$ according to:

$\alpha=\frac{\Delta \omega}{\Delta t}$

$\Delta \omega=\omega_i-\omega_f$

Where $\omega_i$ is the original velocity, in the case the velocity before starting the deceleration, and $\omega_f$ is the final velocity, equal to zero because it has stopped.

$\alpha=\frac{\Delta \omega}{\Delta t} =\frac{\omega_i-\omega_f}{4}\frac{0-445.06}{4} =\frac{-445.06}{4} =-111.26rad/s$

b) To find the distance traveled in radians use the formula:

$\theta = \omega_i t + \frac{1}{2} \alpha t^2$

$\theta = 445.06 (4) + \frac{1}{2}(-111.26) (4)^2=1780.24-890.12=890.12rad$

To change this result to inches, solve the angular displacement $\theta$ for the distance traveled $s$ ( $r$ is the radius).

$\theta=\frac{s}{r} \\s=\theta r$

$s=890.12(5)=4450.6in$

c) The displacement is the difference between the original position and the final. But in every complete rotation of the rim, the point returns to its original position. so is needed to know how many rotations did the point in the 890.16 rad of distant traveled:

$\frac{890.12}{2\pi}=141.6667$

The real difference is in the 0.6667 (or 2/3) of the rotation. To find the distance between these positions imagine a triangle formed with the center of the blade (point C), the initial position (point A) and the final position (point B). The angle $\gamma=\frac{2\pi}{3}=\frac{360^o}{3}=120$ is between the two sides known. Using the theorem of the cosine we can find the missing side of the the triangle(which is also the net displacement):

$c^2=a^2+b^2-2abcos(\gamma)$

$c^2=5^2+5^2-2(5)(5)cos(\frac{2\pi}{3} )\\c^2=25+25+25\\c^2=75\\c=5\sqrt{3}=8.66in$

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4 years ago

The mean diameters of Mars and Earth are 6.9 ✕ 103 km and 1.3 ✕ 104 km, respectively. The mass of Mars is 0.11 times Earth's mas

Roman55 [17]

Answer:

(a) Ratio of mean density is 0.735

(b) Value of g on mars 0.920 $m,/sec^2$

Explanation:

We have given radius of mars $R_{mars}=6.9\times 10^3km=6.9\times 10^6m$ and radius of earth $R_{E}=1.3\times 10^4km=1.3\times 10^7m$

Mass of earth $M_E=5.972\times 10^{24}kg$

So mass of mars $M_m=5.972\times\times 0.11 \times 10^{24}=0.657\times 10^{24}kg$

Volume of mars $V=\frac{4}{3}\pi R^3=\frac{4}{3}\times 3.14\times (6.9\times 10^6)^3=1375.357\times 10^{18}m^3$

So density of mars $d_{mars}=\frac{mass}{volume}=\frac{0.657\times 10^{24}}{1375.357\times 10^{18}}=477.69kg/m^3$

Volume of earth $V=\frac{4}{3}\pi R^3=\frac{4}{3}\times 3.14\times (1.3\times 10^7)^3=9.198\times 10^{21}m^3$

So density of earth $d_{E}=\frac{mass}{volume}=\frac{5.972\times 10^{24}}{9.198\times 10^{21}}=649.271kg/m^3$

(A) So the ratio of mean density $\frac{d_{mars}}{d_E}=\frac{477.69}{649.27}=0.735$

(B) Value of g on mars

g is given by $g=\frac{GM}{R^2}=\frac{6.67\times 10^{-11}\times0.657\times 10^{24}}{(6.9\times 10^6)^2}=0.920m/sec^2$

$v=\sqrt{\frac{2GM}{R}}=\sqrt{\frac{2\times 6.67\times 10^{-11}\times 0.657\times 10^{24}}{6.9\times 10^6}}=3.563\times 10^4m/sec$

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