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Reptile [31]
2 years ago
15

A man weighing 490 N on earth weighs only 81.7 N on the moon. His mass on the moon is ____ kg. (Use g=9.8 m/s²)

Physics
1 answer:
PSYCHO15rus [73]2 years ago
4 0

Answer:

mass= 50kg

since the mass is constant everywhere

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A mom pushes her 19.3 kg daughter on the swing. If she gives her an initial velocity of 7.5 m/s at the bottom of the swing and t
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Answer:

3.17333333333? I hope I get it right

Explanation:

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3 years ago
One mole of an unknown sample contains 120 g of carbon and 30.3 g of
barxatty [35]

atomic mass of carbon is C = 12 g/mol

atomic mass of hydrogen is H = 1 g/mol

now number of carbon atoms

N_c = \frac{120}{12} = 10

Similarly the number of hydrogen atoms are

N_H = \frac{30.3}{1} = 30

so Carbon atom and hydrogen atom must be in ratio of 10:30

so the ratio is 1:3

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5 0
3 years ago
You can, in an emergency, start a manual transmission car by putting it in neutral, letting the car roll down a hill to pick up
Anna [14]

Answer:

The hill should be not less than 0.625 m high

Explanation:

This problem can be solved by using the principle of conservation of mechanical energy. In the absence of friction, the total mechanical energy is conserved. That means that

E_m=U+K is constant, being U the potential energy and K the kinetic energy

U=mgh

K=\frac{mv^2}{2}

When the car is in the top of the hill, its speed is 0, but its height h should be enough to produce the needed speed v down the hill.

The Kinetic energy is then, zero. When the car gets enough speed we assume it is achieved at ground level, so the potential energy runs out to zero but the Kinetic is at max. So the initial potential energy is transformed into kinetic energy.

mgh=\frac{mv^2}{2}

We can solve for h:

h=\frac{v^2}{2g}=\frac{3.5^2}{2(9.8)}=0.625m

The hill should be not less than 0.625 m high

8 0
3 years ago
A cube that is 5.0 cm on a side is made from a material with a density of 800 kg/m3. The cube floats in a fluid that has a densi
laiz [17]

Answer:

Height of the cube under water will be 3.33 cm

Explanation:

We have given height of the cube = 5 cm

Density of the material =800kg/m^3

Density of liquid =1200kg/m^3

We have to find the height of the cube under the water

Height under water is given by

Height under water = \frac{density\ of\ material}{density\ of\ liquid}\times height\ of\ the\ cube=\frac{800}{1200}\times 5=3.33cm

Height of the cube under water will be 3.33 cm

5 0
3 years ago
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