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notsponge [240]
3 years ago
10

On a mission to a newly discovered planet, an astronaut finds chlorine abundances of 13.85 % for 35Cl and 86.15 % for 37Cl. What

is the atomic mass of chlorine for this location? The mass of 35Cl is 34.9700 amu . The mass of 37Cl is 36.9700 amu .
Chemistry
1 answer:
diamong [38]3 years ago
6 0

Answer:

36.693

Explanation:

From the question given, the following were obtained:

Let 35Cl be isotope A and 37Cl be isotope

For isotope A (35Cl),

Mass number = 34.9700

Abundance = 13.85 %

For isotope B (37Cl),

Mass number = 36.9700

Abundance = 86.15 %

Atomic mass =

[( Mass of AxAbundance A)/100] + [(Mass of BxAbundance B)/100]

[(34.97x13.85)/100] + [(36.97x86.15)/100]

= 36.693

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Based on the diagram below, how much of the excess reactant is left over? *
pantera1 [17]

Answer:

3 pieces of lunch-meat and 2 slices of cheese

Explanation:

You have enough bread to make 3 sandwiches

You have enough lunch-meat to make 4 sandwiches

You have enough cheese to make 5 sandwiches

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5 0
3 years ago
An excess of oxygen reacts with 451.4 g of lead, forming 374.7 g of lead(II) oxide. Calculate the percent yield of the reaction.
Stels [109]

Answer: The percent yield of the reaction is 77.0 %

Explanation:

2Pb+O_2\rightarrow 2PbO

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Number of moles of lead}=\frac{451.4g}{207.2g/mol}=2.18moles

\text{Number of moles of lead oxide}=\frac{374.7g}{223.2g/mol}=1.68moles

According to stoichiometry:

2 moles of Pb produces = 2 moles of PbO_2

2.18 moles of Pb is produced by=\frac{2}{2}\times 2.18=2.18moles of PbO_2

Mass of PbO_2 =moles\times {\text {Molar mass}}=2.18\times 223.2g/mol=486.6

percent yield =\frac{374.7g}{486.6g}\times 100=77.0\%

3 0
3 years ago
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