Question

g The instruction booklet for your pressure cooker indicates that its highest setting is 12.5 psipsi . You know that standard atmospheric pressure is 14.7 psi psi, so the booklet must mean 12.5 psipsi above atmospheric pressure. At what temperature in degrees Celsius will your food cook in this pressure cooker set on "high"

Answer 1

Answer:

$278.25^0C$

Explanation:

In this case, Gay-Lussac's law is used to compute the required temperature, as it relates pressure and temperature, by knowing that the atmospheric standard temperature is 25 °C, as follows:

$P_1T_2=P_2T_1$

Thus, the initial pressure is known as 14.7 psi and the initial temperature 25 °C, which correspond to the atmospheric conditions. Nonetheless, the pressure into the cooker, should be:

$P_2=12.5psi+14.7psi=27.2psi$

Since the 12.5 psi are above the atmospheric pressure. In such a way, the temperature inside the cooker turns out:

$T_2=\frac{P_2*T_1}{P_1}=\frac{27.2psi*(25+273.15)K}{14.7psi} =551.4K=278.25^0C$

Best regards.