The empirical formula for this vitamin : C₃H₄O₃
<h3>Further explanation
</h3>
The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components
The principle of determining empirical formula
- Determine the mass ratio of the constituent elements of the compound.
- Determine the mole ratio by dividing the percentage by the atomic mass
Mass of C in CO₂ :(MW C = 12 g/mol, CO₂=44 g/mol)
Mass of H in H₂O :(MW H = 1 g/mol, H₂O = 18 g/mol)
Mass O = Mass sample - (mass C + mass H) :
mol ratio C : H : O =
They loose a valence electron
if you have 1.27*10^-36= [Cu2+][X2-] then you can set both those values equal to x because they're stoichimetrically equal.
1.27*10^-36=x^2
Take the square root of both sides.
1.13*10^-18=x
That would be your solubility.
Answer:
The alkali metals consist of the chemical elements lithium, sodium, potassium, rubidium, caesium, and francium. Together with hydrogen, they constitute group 1, which lies in the s-block of the periodic table
The alkali metals are all shiny, soft, highly reactive metals at standard temperature and pressure and readily lose their outermost electron to form cations with charge +1.
The mass of reactant that would produce 800 Joules of heat is equal to 800 J × (1 kJ/1000 J)/(24.7 kJ/g).
<h3>How to calculate the mass of reactant?</h3>
In order to determine the mass of reactant that would produce 800 Joules of heat, we would set up a conversion equation as follows:
<u>Note:</u> 1 kJ is equal to 1000 Joules.
<u>Conversion:</u>
1 gram = 24.7 kJ
X gram = 800 Joules
Therefore, the mass of reactant that would produce 800 Joules of heat is given by:
Mass = Heat × (conversion factor/rate of heat)
Mass = 800 J × (1 kJ/1000 J)/(24.7 kJ/g).
Read more on heat here: brainly.com/question/5140667
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<u>Complete Question:</u>
A certain chemical reaction releases 24.7 kJ/g of heat for each gram of reactant consumed. How can you calculate what mass of reactant will produce 800 Joules of heat?
