Answer:
152 kPa = Partial pressure O₂
Explanation:
Data by percent is the molar fraction . 100.
Molar fraction of Helium = 32/ 100 → 0.32
Molar fraction of O₂ = 68/100 → 0.68
Sum of molar fractions in a mixture = 1
0.68 + 0.32 = 1
If we apply the molar fraction, we can determine the partial pressure.
Mole fraction = Partial pressure / Total pressure
0.32 = Partial pressure O₂ / 475kPa → 0.32 . 475 kPa = Partial pressure O₂
152 kPa = Partial pressure O₂
Answer:
B) iron (Fe) im sure its iron
They are both on animals (not humans). IDK, maybe?
For the reaction of deprotonation of formic acid, the concentration of HCOO⁻ at equilibrium is 0.0151 M if the initial concentration of formic acid is 1.35 M.
The reaction of deprotonation of formic acid is the following:
CHOOH + H₂O ⇄ HCOO⁻ + H₃O⁺
At the equilibrium we have:
CHOOH + H₂O ⇄ HCOO⁻ + H₃O⁺ (1)
1.35 - x x x
The acid <em>equilibrium </em>constant for this reaction is:
(2)
Entering the values of [CHOOH] = 1.35-x, [HCOO⁻] = [H₃O⁺] = x, into equation (2) we have:

After solving the above <em>quadratic equation</em> and taking the positive value for x (<u>concentrations cannot be negative</u>), we have:
Therefore, the concentration of HCOO⁻ at equilibrium is 0.0151 M.
Learn more about the equilibrium constant here:
I hope it helps you!