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goblinko [34]
3 years ago
8

You purchase 5 pounds of cheese for $28. How much would 1 quart of cheese cost?

Mathematics
1 answer:
Vikentia [17]3 years ago
7 0

Answer:

You would get 1.4

Step-by-step explanation:

First you divide 5 pounds by $28 your answer will be :<em> </em><em>5</em><em>.</em><em>6</em>

Than you divide 5.6 by 4 because 4 quarters make 1 whole

So, you divide 5.6 by 4

Than you get the answer 1.4.

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3 years ago
Set A of six numbers has a standard deviation of 3 and set B of four numbers has a standard deviation of 5. Both sets of numbers
Alenkinab [10]

Given:

\sigma_A=3

n_A=6

\sigma_B=5

n_B=4

\overline{x}_A=\overline{x}_B

To find:

The variance. of combined set.

Solution:

Formula for variance is

\sigma^2=\dfrac{\sum (x_i-\overline{x})^2}{n}      ...(i)

Using (i), we get

\sigma_A^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{n_A}

(3)^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}

9=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}

54=\sum (x_i-\overline{x}_A)^2

Similarly,

\sigma_B^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{n_B}

(5)^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}

25=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}

100=\sum (x_i-\overline{x}_B)^2

Now, after combining both sets, we get

\sigma^2=\dfrac{\sum (x_i-\overline{x}_A)^2+\sum (x_i-\overline{x}_B)^2}{n_A+n_B}

\sigma^2=\dfrac{54+100}{6+4}

\sigma^2=\dfrac{154}{10}

\sigma^2=15.4

Therefore, the variance of combined set is 15.4.

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3 years ago
Consider the steps for solving 3x2 – 42x + 9 = -5 for x by completing the square.
Karolina [17]
The answer to this question will be C
3 0
4 years ago
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