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Luda [366]
3 years ago
10

Four year old Sam has erotically tinged desires for his mother and also feels hostile towards his father. Freud would conclude t

hat Sam is experiencing the
Physics
1 answer:
sergij07 [2.7K]3 years ago
3 0

Answer:

Oedipal complex.

Explanation:

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In middle ages people believed that abnormal behavior was cause by ?
Svetach [21]
C, they didn't know any better
8 0
3 years ago
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A projectile is launched straight up from a height of 960 feet with an initial velocity of 64 ft/sec. Its height at time t is h(
Natasha2012 [34]

Answer:

a) t=2s

b) h_{max}=1024ft

c) v_{y}=-256ft/s

Explanation:

From the exercise we know the initial velocity of the projectile and its initial height

v_{y}=64ft/s\\h_{o}=960ft\\g=-32ft/s^2

To find what time does it take to reach maximum height we need to find how high will it go

b) We can calculate its initial height using the following formula

Knowing that its velocity is zero at its maximum height

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

0=(64ft/s)^2-2(32ft/s^2)(y-960ft)

y=\frac{-(64ft/s)^2-2(32ft/s^2)(960ft)}{-2(32ft/s^2)}=1024ft

So, the projectile goes 1024 ft high

a) From the equation of height we calculate how long does it take to reach maximum point

h=-16t^2+64t+960

1024=-16t^2+64t+960

0=-16t^2+64t-64

Solving the quadratic equation

t=\frac{-b±\sqrt{b^{2}-4ac}}{2a}

a=-16\\b=64\\c=-64

t=2s

So, the projectile reach maximum point at t=2s

c) We can calculate the final velocity by using the following formula:

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

v_{y}=±\sqrt{(64ft/s)^{2}-2(32ft/s^2)(-960ft)}=±256ft/s

Since the projectile is going down the velocity at the instant it reaches the ground is:

v=-256ft/s

5 0
3 years ago
Blue light of wavelength λ passes through a single slit of width d and forms a diffraction pattern on a screen. If we replace th
ololo11 [35]

Answer:

We can retain the original diffraction pattern if we change the slit width to d) 2d.

Explanation:

The diffraction pattern of a single slit has a bright central maximum and dimmer maxima on either side. We will retain the original diffraction pattern on a screen if the relative spacing of the minimum or maximum of intensity remains the same when changing the wavelength and the slit width simultaneously.

Using the following parameters: <em>y</em> for the distance from the center of the bright maximum to a place of minimum intensity, <em>m</em> for the order of the minimum, <em>λ </em>for the wavelength, <em>D </em>for the distance from the slit to the screen where we see the pattern and <em>d </em>for the slit width. The distance from the center to a minimum of intensity can be calculated with:

                                                    y\approx\frac{m\lambda D}{d}

From the above expression we see that if we replace the blue light of wavelength λ by red light of wavelength 2λ in order to retain the original diffraction pattern we need to change the slit width to 2d:

<em>                                                 </em>y\approx\frac{m\lambda D}{d} =\frac{m2\lambda D}{2d}

7 0
3 years ago
When an object experiences centripetal acceleration, in which direction does it accelerate?
tatuchka [14]

Centripetal acceleration points from the object toward the center of the circular path it's traveling.

3 0
3 years ago
Read 2 more answers
Find the acceleration of a car with a mass of 1,200 kg and a force of 11,000 N.<br> Please help
netineya [11]

Answer:

9.17 m/s^2

Explanation:

Formula for force is given by

F = m*a

where F is the force in newton

m is the mass of body in KG

and

a is the acceleration of body on m/s^2

_______________________________________________

Given

F = 11,000

mass = 1,200 Kg

we have to find value of acceleration

using

F = m*a

11,000 = 1200*a

=> a = 11,000 /1200 = 9.17

Thus, the acceleration of a car is 9.17 meter per second square

5 0
3 years ago
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