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bearhunter [10]
3 years ago
14

What time was it 2011 minutes after the beginning of January 1

Mathematics
1 answer:
PIT_PIT [208]3 years ago
8 0
Okay! 

Notable things in the problem:
2011 <u>minutes</u> <u>AFTER</u> the beginning of January 1rst. 

12:00AM will be our starting time, because that's when January 1rst begins. 
It'll be a bit easier to work with if we convert the 2011 minutes into hours. 
So take 2011 minutes and divide it by 60 to get the number of hours. 

2011 / 60 = 33 hours and 31 minutes

You wouldn't be able to easily get the exact number of minutes from a calculator. You'll need to use long division. The remainder will be the number of minutes. If you want to check you can multiply the number of hours by 60 and add 31 to the product. If it doesn't equal 2011 minutes then something is amiss. 

12:00 AM 

Since we know this is a 24 hour clock we can subtract 24 from our number of hours. (Just remember that this is the next day) 

12:00 AM with 9 hours and 31 minutes left. 

9:31 AM a day later is our time!<u />
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The equation 6x - 5y = 14 is written in standard form. Which point lies on
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Hank has to drain his pool so repairs can be done on a crack on the bottom. The company coming to fix the pool is scheduled to a
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Answer:

The answer to the question: "Will Hank have the pool drained in time?" is:

  • <u>Yes, Hank will have the pool drained in time</u>.

Step-by-step explanation:

To identify the time Hank needs to drain the pool, we can begin with the time Hank has from 8:00 AM to 2:00 PM in minutes:

  • Available time = 6 hours * 60 minutes / 1 hour (we cancel the unit "hour")
  • Available time =  360 minutes

Now we know Hank has 360 minutes to drain the pool, we're gonna calculate the volume of the pool with the given measurements and the next equation:

  • Volume of the pool = Deep * Long * Wide
  • Volume of the pool = 2 m * 10 m * 8 m
  • Volume of the pool = 160 m^3

Since the drain rate is in gallons, we must convert the obtained volume to gallons too, we must know that:

  • 1 m^3 = 264.172 gal

Now, we use a rule of three:

If:

  • 1 m^3 ⇒ 264.172 gal
  • 160 m^3 ⇒ x

And we calculate:

  • x = \frac{160 m^{3}*264.172 gal }{1m^{3} } (We cancel the unit "m^3)
  • x = 42267.52 gal

At last, we must identify how much time take to drain the pool with a volume of 42267.52 gallons if the drain rate is 130 gal/min:

  • Time to drain the pool =\frac{42267.52gal}{130\frac{gal}{min} }(We cancel the unit "gallon")
  • Time to drain the pool = 325.1347692 minutes
  • <u>Time to drain the pool ≅ 326 minutes</u> (I approximate to the next number because I want to assure the pool is drained in that time)

As we know, <u><em>Hank has 360 minutes to drain the pool and how it would be drained in 326 minutes approximately, we know Hank will have the pool drained in time and will have and additional 34 minutes</em></u>.

7 0
3 years ago
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