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2 years ago

What element is a non-metal. A. Mg B. Rb C. Li D. Br E. Si

Chemistry

2 answers:

Goryan [66]2 years ago

4 0

Answer:

D.) Br

Explanation:

I don’t really have an explanation.

I hope this helps!

zaharov [31]2 years ago

4 0

Br

i can’t explain this but Bromine is not a metal

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__HgO __Hg + __O2 what is the reaction

Gelneren [198K]

Answer:

2HgO <---- 2Hg + O2

Explanation:

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3 years ago

Part III.The two reactions involved in quantitatively determining the amount of iodate in solution are: IO3-(aq) 5 I-(aq) 6 H (a

slega [8]

Answer:

$\large \boxed{\math{\dfrac{\text{6 mol thiosulfate}}{\text{1 mol iodate}}}}$

Explanation:

The I₂ is the common substance in the two equations.

(1) IO₃⁻ + 5I⁻ + 6H⁺ ⟶ 3I₂ + 3H₂O

{2) I₂ + 2S₂O₃²⁻ ⟶ 2I⁻ + S₄O₆²⁻

From Equation (1), the molar ratio of iodate to iodine is

$\dfrac{\text{I}_{2}}{\text{IO}_{3}^{-}} = \dfrac{3}{1}$

From Equation (2), the molar ratio of iodine to thiosulfate is

$\dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{I}_{2}} = \dfrac{2}{1}$

Combining the two ratios, we get

$\text{Stoichiometric factor} = \dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{IO}_{3}^{-}} = \dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{I}_{2}} \times \dfrac{\text{I}_{2}}{\text{IO}_{3}^{-}} = \dfrac{2}{1} \times \dfrac{3}{1} = \mathbf{\dfrac{6}{1}}\\\\\text{The stoichiometric factor is $\large \boxed{\mathbf{\dfrac{\text{6 mol thiosulfate}}{\text{1 mol iodate}}}}$}$

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3 years ago

What is the pH of a solution that has a pOH of 5.9

Stella [2.4K]

Answer:

pH = 8.1

Explanation:

Assuming that we are at 25 degrees Celsius, pH + pOH = 14.

We can then plug in the given pOH and solve for pH:

pH + pOH = 14

pH + 5.9 = 14

pH = 14 - 5.9 = 8.1

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3 years ago

The small 2 next to Nitrogen is called the ____.

klasskru [66]

1. Subscript is below
2. Coefficient large 2 indicates the number of moles
3. Atoms
1/2 O2 + H2 —> H2O
It’s the atoms that balance on each side
Notes that 1/2 is the coefficient and 2 is the subscript in H2 and H2O

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3 years ago

Read 2 more answers

A concentration cell consists of two zn/zn2+ electrodes. the electrolyte in compartment a is 0.10 m zn(no3)2 and in compartment

Dmitrij [34]

Answer:

E= -0.023V

Explanation:

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3 years ago