Answer:
b
Explanation:
it's b because I just went over that frome my class and got it correct
Explanation:
my God what kinda learning you doing?
Answer:
a) atoms Pb = 4.3595 E22 amu
b) g = ( 6.022 E23 amu ) × ( Mw )
Explanation:
sample:
∴ m = 15.00 g
a) atoms Pb = ?
⇒ atoms Pb = (15.00g Pb)(mol Pb/207.2 g)(6.022 E23 amu/mol)
⇒ atoms Pb = 4.3595 E22 amu
b) relationship:
∴ 1 mol (n) ≡ 6.022 E23 amu......(1)
∴ mass (g) ≡ (Mw)×(n)
⇒ n = g / Mw..........(2)
∴ Mw: molecular weight
(1) = (2):
⇒ g / Mw ≡ 6.022 E23 amu
⇒ g ≡ ( 6.022 E23 amu ) × ( Mw )
<u>Answer:</u> The volume of stock solution of ammonia that is needed is 48.67 mL
<u>Explanation:</u>
To calculate the volume of stock solution, we use the equation:
where,
are the molarity and volume of the stock ammonia solution
are the molarity and volume of diluted ammonia solution
We are given:
Putting values in above equation, we get:
Hence, the volume of stock solution of ammonia that is needed is 48.67 mL
