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Yuri [45]
3 years ago
12

A cart is pulled by a force of 250 N at an angle of 35° above the horizontal. The cart accelerates at 1.4 m/s2. The free-body di

agram shows the forces acting on the cart.
A free body diagram with 3 force vectors. The first vector is pointing downward, labeled F Subscript g Baseline. The second vector is pointing up, labeled F Subscript N Baseline. The third vector is pointing up to the right at an angle of 35 degrees, labeled F Subscript p Baseline = 250 N. The up and down vectors are the same length.

The mass of the cart, to the nearest whole number, is
Physics
2 answers:
faust18 [17]3 years ago
6 0

Answer:

146kg

Explanation:

right on edge

Pachacha [2.7K]3 years ago
4 0

Answer:

m=146.277kg which is rounded to 146kg

Explanation:

Remember that F=ma

But F represents not 250N, but 250cos(35)N since the force is being pulled above the horizontal.

So 250cos(35)=204.7880111 approximately, and since a=1.4m/s^2, we have 204.7880111=m(1.4m/s^2). Then we divide both sides by the acceleration to get the mass. So m=146.2771508kg which the nearest number is 146kg

Mass is always in kg, unless stated otherwise.

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slavikrds [6]

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Explanation:

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<em><u>If I double the current in the inductor, the new total energy will become 4E (option f).</u></em>

3 0
3 years ago
Given Vout = 17.33 vpp and R1 = 3 kΩ, find the value of RF required to provide Av = 4.33. (Round your answer to 2 decimal places
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Answer:

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Explanation:

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For finding input voltage we use,

   A_{v} = \frac{V_{out} }{V_{2} }

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The Phase of V_{2} is zero because output voltage phase is 360°

Therefore, the magnitude of V_{2} is 4 V and phase of input voltage is zero

7 0
3 years ago
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