A cart is pulled by a force of 250 N at an angle of 35° above the horizontal. The cart accelerates at 1.4 m/s2. The free-body di
2 answers:
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Answer:
Explanation:
In order to solve this question, we would need to incorporate Stoichiometry, which involves using relationships between reactants and/or products in a chemical reaction to determine desired quantitative data.
Here's a balanced equation for the reaction:
Let us define work as;
where
External pressure is given as , therefore the work solely depends on the change in volume and since the reactants are solids, none of the reactants contribute to the volume. Hence,
To find the volume of the products, we need to first find the amount of moles of the product made from using the molar mass of
which is 101.1032 g/mol
Now let us convert moles of into moles of
and
using the stoichiometric ratios from our balanced equation of the reaction.
is not factored into the volume calculation because it is a solid.
Now let us also convert the moles of and
into grams using their respective molar masses.
We will now proceed to convert grams into volume using the density values provided.
Summing up the two volumes, we get the final volume
Plugging everything into the equation, we get:
Finally, let us convert into joules using the conversion rate of;
Answer:
Explanation:
This is a 2D problem (parabolic) so we have to think that way. We have to split up the problem into its 2 dimensions to solve it. Think "y-stuff" and "x-stuff".
In the y-stuff category:
v₀ = 0 (initial upwards velocity is 0 since we are told the penny is thrown horizontally)
Δx = -10.0 m (this displacement is negative because the penny lands 10.0 m below the point from which it was thrown)
a = -9.8 m/s/s
t = ? (we need to find the time in this dimension so we can use it in the x dimension to find the displacement, our unknown)
In the "x-stuff" category:
v₀ = 7.25 m/s (this is given)
Δx = ???
a = 0 (acceleration in this dimension is ALWAYS 0)
t = (we will solve for this in the y-dimension and plug it in here).
In the y dimension:
Δx = v₀t + and plugging in from the y-dimension info:
which simplifies to
so
which, to 2 significant digits is
t = 1.4 seconds
Now we will do the same in the x-dimension, using t = 1.4:
Δx = v₀t + and filling in the x-stuff:
Δx = Notice that the stuff after the + sign goes to 0 cuz of the multiplication of 0, so what we are left with is another form of the d = rt equation:
Δx = 7.25(1.4) + 0 so
Δx = 1.0 × 10¹ m (That's rounded correctly to 2 sig dig's: 10 m from the base of the building).