Ask question

Ask question

All categories

Morgarella [4.7K]

3 years ago

9

Often a radical change in the form of the solution of a differential equation corresponds to a very small change in either the i

nitial condition or the equation itself. Find an explicit solution of the given initial-value problem.

1 answer:

skad [1K]3 years ago

6 0

Answer: see attachment

Step-by-step explanation:

See attachment

You might be interested in

What is the slope line perpendicular to the equation 4x+3y=9

aleksandrvk [35]

Answer:

m=3/4

Step-by-step explanation:

first, let's put the line 4x+3y=9 from standard form (ax+by=c) into slope-intercept form (y=mx+b)

we have the equation 4x+3y=9

subtract 4x from both sides

3y=-4x+9

divide by 3

y=-4/3x+3

perpendicular lines have slopes that are negative and reciprocal. If the slopes are multiplied together, the result is -1

so to find the slope of the line perpendicular to the line y=-4/3x+3, we can take the slope of y=-4/3x+3 (-4/3) multiply it by a variable (this is our unknown value), and have that set to -1

(m is the slope value)

-4/3m=-1

multiply by -3/4

m=3/4

therefore the slope of the perpendicular line is 3/4

hope this helps!! :)

7 0

3 years ago

2. The cost that a carpet cleaning company charges is directly proportional to the number of rooms cleaned. The cost is $22 for

kvv77 [185]

<span>The cost that a carpet cleaning company charges is directly proportional to the number of rooms cleaned. The cost is $22 for each room.</span>

5 0

3 years ago

Read 2 more answers

A triangle is graphed in the coordinate plane. The vertices of the triangle have coordinates (–3, 1), (1, 1), and (1, –2). What

vladimir2022 [97]

Answer:

The perimeter of the triangle is $12\ units$

Step-by-step explanation:

Let

$A(-3,1),B(1,1),C(1,-2)$

we know that

The perimeter of triangle is equal to

$P=AB+BC+AC$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$A(-3,1),B(1,1)$

substitute in the formula

$AB=\sqrt{(1-1)^{2}+(1+3)^{2}}$

$AB=\sqrt{(0)^{2}+(4)^{2}}$

$AB=4\ units$

step 2

Find the distance BC

$B(1,1),C(1,-2)$

substitute in the formula

$BC=\sqrt{(-2-1)^{2}+(1-1)^{2}}$

$BC=\sqrt{(-3)^{2}+(0)^{2}}$

$BC=3\ units$

step 3

Find the distance AC

$A(-3,1),C(1,-2)$

substitute in the formula

$AC=\sqrt{(-2-1)^{2}+(1+3)^{2}}$

$AC=\sqrt{(-3)^{2}+(4)^{2}}$

$AC=5\ units$

step 4

Find the perimeter

$P=AB+BC+AC$

substitute the values

$P=4+3+5=12\ units$

6 0

4 years ago

How to write a math phrase in algebraic expressions

Maksim231197 [3]

2^5*2=? I think but ok whatever

5 0

3 years ago

Read 2 more answers

What is the prime factorization of the number 45

ohaa [14]

..........................

7 0

4 years ago

Read 2 more answers