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Scilla [17]
3 years ago
7

What is cosmic ray spallation

Physics
2 answers:
love history [14]3 years ago
6 0

The Cosmic Ray is a natural way for nuclear fission and nucleosynthesis to occur. It refers to the formation of chemical elements from the impact of cosmic rays on an object.

tigry1 [53]3 years ago
6 0

Cosmic ray spallation is a form of naturally occurring nuclear fission and nucleosynthesis

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10. A child drops a ball from a window. The ball strikes the ground in 3.0 seconds. What is the velocity of the ball the instant
vladimir1956 [14]
The velocity of the ball is 30.0 m/s.
5 0
2 years ago
Three masses are located in the x- y plane as follows: a mass of 6 kg is at (0 m, 0 m), a mass of 4 kg is at (3 m, 0 m), and a m
enot [183]

Answer:

The center of mass of three mass in the x-y plane is located at (1,0.5).                  

Explanation:

It is given that, a mass of 6 kg is at (0,0), a mass of 4 kg is at (3,0), and a mass of 2 kg is at (0,3). We need to find the center of mass of the system. Center of mass in x direction  is :

C_x=\dfrac{6\times 0+4\times 3+2\times 0}{6+4+2}\\\\C_x=1

The center of mass in y direction is :

C_y=\dfrac{6\times 0+4\times 0+2\times 3}{6+4+2}\\\\C_y=0.5

So, the center of mass of three mass in the x-y plane is located at (1,0.5).

3 0
3 years ago
Mandy is testing an unknown solution to determine whether it is an acid or a base. She places a piece of red litmus paper into t
Marina CMI [18]
The solution is a base
5 0
2 years ago
Find the displacement in meters a runner would travel in 5 hours at an average velocity of 12km/h to the southwest
vova2212 [387]

Answer:

60,000m

Explanation:

Convert km/h to m/s by multiplying with 1000/3600.

Convert hours to seconds by multiplying with 3600.

Because displacement is a vector quantity and deals with the shortest distance between points, simply plug it into the equation s=vt.

8 0
3 years ago
A typical neutron star may have a mass equal to that of the Sun but a radius of only 20 km.(a) What is the gravitational acceler
Pepsi [2]

Answer:

331665750000\ m/s^2

3257806.62409 m/s

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of Sun = 1.989\times 10^{30}\ kg

r = Radius of Star = 20 km

u = Initial velocity = 0

v = Final velocity

s = Displacement = 16 m

a = Acceleration

Gravitational acceleration is given by

g=\dfrac{GM}{r^2}\\\Rightarrow g=\dfrac{6.67\times 10^{-11}\times 1.989\times 10^{30}}{20000^2}\\\Rightarrow g=331665750000\ m/s^2

The gravitational acceleration at the surface of such a star is 331665750000\ m/s^2

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 331665750000\times 16+0^2}\\\Rightarrow v=3257806.62409\ m/s

The velocity of the object would be 3257806.62409 m/s

8 0
3 years ago
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