Answer:
The length of the unknown sides of the triangles are as follows:
CD = 10√2
AC = 10√2
BC = 10
AB = 10
ΔACD is a right angle triangle. Therefore, Pythagoras theorem can be used to find the sides of the triangle.
c² = a² + b²
where
c = hypotenuse side = AD = 20
a and b are the other 2 legs
lets use trigonometric ratio to find CD,
cos 45 = adjacent / hypotenuse
cos 45 = CD / 20
CD = 1 / √2 × 20
CD = 20 / √2 = 20√2 / 2 = 10√2
20² - (10√2)² = AC²
400 - 100(2) = AC²
AC² = 200
AC = √200 = 10√2
ΔABC is a right angle triangle too. Therefore,
AB² + BC² = AC²
Using trigonometric ratio,
cos 45 = BC / 10√2
BC = 10√2 × cos 45
BC = 10√2 × 1 / √2
BC = 10√2 / √2 = 10
(10√2)² - 10² = AB²
200 - 100 = AB²
AB² = 100
AB = 10
Step-by-step explanation:
Answer: the second one
Step-by-step explanation:
3x9=27
21/3 = 7
so
7+27x9+5
27x9=243
243+7+5
answer is 255
I post an image instead.
Correction: g(3)=(3²)|3|=9(3)=27
Answer:
y=1/2x-3
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-7-(-1))/(-8-4)
m=(-7+1)/-12
m=-6/-12
m=1/2
y-y1=m(x-x1)
y-(-1)=1/2(x-4)
y+1=1/2x-4/2
y=1/2x-2-1
y=1/2x-3
