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4 years ago

Apply the distributive property to create an equivalent expression. 1/2 (2a - 6b+ 8)

Mathematics

1 answer:

kykrilka [37]4 years ago

7 0

The answer is A-3b+4

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What are the steps for this problem? -10-8n=n-(8n+8)

Elden [556K]

Answer:

$n = - 2$

Step-by-step explanation:

$- 10 - 8n = n - (8n + 8)$

First, you should distribute the -1 on the right.

$- 10 - 8n = n - 8n - 8$

Next, add 8n to both sides. This should cancel out the 8n.

$- 10 = n - 8$

Now, add 8 to both sides. This will get n by itself.

$- 2 = n$

Your answer is n = -2.

6 0

4 years ago

Read 2 more answers

A rectangular prism is completely packed with 63 cubes of edge length fraction 1 over 3 inch, without any gap or overlap.

77julia77 [94]

Answer:

2 1/3 cubic inches

Step-by-step explanation:

Perhaps you want to know the volume of the prism in cubic inches.

Find the total volume of the smaller cubes:

63(1/3 in)^3 = 63/27 in^3 = 7/3 in^3 = 2 1/3 in^3

4 0

3 years ago

Abram and Fred leave opposite ends of a bike trail 12 miles apart and travel toward each other. Abram is traveling 8 mph faster

Dimas [21]

Abram: 10 mph; Fred: 7 mph

8 0

3 years ago

Which point is a solution to the system of equations?<br> y = 3x +4<br> y =+2

Andru [333]

(-2/3, 2)

Solve for the first variable in one of the equations, then substitute the result into the other equation.

3 0

3 years ago

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What is the remainder R when the polynomial p(x) is divided by (x + 1)? Is (x + 1) a factor of p(x)? p(x) = -3x4 + 2x3 - x2 + 6

vodka [1.7K]

Answer:

(x+1) is a factor with remainder 0.

Step-by-step explanation:

We divide (x+1) into the polynomial $-3x^4+2x^3-x^2+6$ through long division or synthetic. We choose long division and look for what will multiply with (x+1) to make the polynomial $-3x^4+2x^3-x^2+6$ .

$(x+1)(-3x^3)=-3x^4-3x^3$

We subtract this from the original $-3x^4-(-3x^4)+2x^3-(-3x^3)-x^2+6$ .

This leaves $5x^3-x^2+6$ . We repeat the step above.

$(x+1)(5x^2)=5x^3+5x^2$ .

We subtract this from $5x^3-(5x^3)-x^2-(5x^2)+6=-6x^2+6$ . We repeat the step above.

$(x+1)(-6x)=-6x^2-6x$ .

We subtract this from $-6x^2-(-6x^2)+0x-(-6x)+6=6x+6$ . We repeat the step above.

$(x+1)(6)=-6x+1$ .

We subtract this from $6x-(6x)+6-(6)=0$ . There is no remainder. This means (x+1) is a factor.

7 0

3 years ago