Answer:
162.78 m/s is the most probable speed of a helium atom.
Explanation:
The most probable speed:
= Boltzmann’s constant =
T = temperature of the gas
m = mass of the gas particle.
Given, m = 
T = 6.4 K
Substituting all the given values :
162.78 m/s is the most probable speed of a helium atom.
Answer:
<h3>The binding energy of sodium Na=<em>5.407791×10⁹J</em></h3>
Explanation:
<h3>Greetings !</h3>
Binding energy, amount of energy required to separate a particle from a system of particles or to disperse all the particles of the system. Binding energy is especially applicable to subatomic particles in atomic nuclei, to electrons bound to nuclei in atoms, and to atoms and ions bound together in crystals.
<h2>Formula : Eb=(Δm)c²</h2><h3>where:Eb= binding energy</h3><h3> .Δm= mass defect(kg)</h3><h3> c= speed of light 3.00×10⁸ms¯¹</h3><h2 /><h3>
<u>Given</u><u> </u><u>values</u></h3>
- m= 18.02597
- c=3.00×10⁸ms¯¹
<h3><u>required </u><u>value</u></h3>
<h3><u>Solution:</u></h3>
- Eb=(Δm)c²
- Eb=(18.02597)*(3.00*10⁸ms¯¹
- Eb=5.407791*10⁹J
The average speed is determined by the following formula:
average speed = [sum of (speed * time for which that speed was traveled)] / total time
average speed = [(83 * 26 + 41 * 52 + 60 * 45 + 0 * 15) / 60] / [(26 + 52 + 45 + 15) / 60]
*note: The division by 60 is to convert minutes to hours. We see that the 60 cancels from the top and bottom of the division
average speed = 50.65 km/hr
The total distance traveled is equivalent to the numerator of the fraction we used in the first part. This is:
Distance = (83 * 26 + 41 * 52 + 60 * 45 + 0 * 15) / 60
Distance = 116.5 kilometers
Answer:
a,b) #_ {electron} = 1.64 10¹⁹ electrons, c) R = 19.54 Ω, d) V = 10.3 V
Explanation:
a and b) The current is defined as the number of electrons that pass per unit of time
let's look for the load
Q = I t
Q = 0.526 5
Q = 2.63 C
Let's use a direct rule of three proportions. If an electron has a charge of 1.6 10⁻¹⁹ C, how many electrons does 2.63 C have?
#_ {electron} = 2.63 C (1 electron / 1.6 10⁻¹⁹)
#_ {electron} = 1.64 10¹⁹ electrons
c) the resistance of a wire is given by
R = ρ l / A
where the resistivity of tungsten is 5.6 10⁻⁸ Ω
the area of the wire is
A = π r2 = π d²/4
we substitute
R = 
let's calculate
R = 5.6 10⁻⁸ 0.580 
R = 19.54 Ω
d) let's use ohm's law
V = i R
V = 0.526 19.54
V = 10.3 V
Answer:
Explanation:
a) Power consumption is 4100 J/min / 60 s/min = 68.3 W(atts)
work done raised the potential energy
b) 75(9.8)(1000) / (3(3600)) = 68.055555... 68.1 W
c) efficiency is 68.1 / 68.3 = 0.99593... or nearly 100%
Not a very likely scenario.
