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mario62 [17]
3 years ago
9

Calculate the volume of a tin block that has a mass of 95.04 grams at STP. Your response must include both a numerical setup and

the calculated result.
Element Density at STP (g/cm3)C 3.51Si 2.33Ge 5.32Sn 7.31Pb 11.35
Chemistry
1 answer:
Ahat [919]3 years ago
3 0

Answer:

Explanation:

As the problem states that we have STP, these conditions are 1 atm of pressure and 273 K of temperature.

Now, the equation we must use to solve this:

PV = nRT

Solving for V:

<em>V = nRT/P</em>

<em>Where:</em>

<em>V: Volume in Liters</em>

<em>n: moles of the tin block</em>

<em>T: temperature in K</em>

<em>P: Pressure in atm</em>

<em>R: gas constant which is 0.082 L atm / K mol</em>

But also the problem is giving us the density data for all elements. In the case of Tin it is 7.31 g/cm³ or 7.31 g/mL, so, with the formula of density:

<em>d = m/V  ----> V = m/d</em>

From the above formula, we can calculate the volume of tin so:

V = 95.04 / 7.31

<em>V = 13 mL</em>

This would be the volume of the tin block, but, we have this block at STP so we need to calculate the volume with the ideal gas equation above. We need the molecular mass of Tin which is 118.71 g/mol, so let's calculate the moles:

n = m/MM

n = 95.04 / 118.71 = 0.8 moles

Now, solving for V:

V = 0.8 * 0.082 * 273 / 1

<em>V = 17.91 L</em>

<em>And this would be the volume of the tin block at STP conditions.</em>

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Fe2O3 + CO --&gt; Fe + CO2
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Answer:

The answer to your question is

1.-Fe₂O₃

2.- 280 g

3.- 330 g

Explanation:

Data

mass of CO = 224 g

mass of Fe₂O₃ = 400 g

mass of Fe = ?

mass of CO₂

Balanced chemical reaction

                       Fe₂O₃   + 3CO    ⇒  2Fe  +   3CO₂

1.- Calculate the molar mass of Fe₂O₃ and CO

Fe₂O₃ = (56 x 2) + (16 x 3) = 160 g

CO = 12 + 16 = 28 g

2.- Calculate the proportions

theoretical proportion Fe₂O₃ /3CO = 160/84 = 1.90

experimental proportion Fe₂O₃ / CO = 400/224 = 1.78

As the experimental proportion is lower than the theoretical, we conclude that the Fe₂O₃ is the limiting reactant.

3.-     160 g of Fe₂O₃  --------------- 2(56) g of Fe

         400 g of Fe₂O₃ ---------------  x

         x = (400 x 112) / 160

        x = 280 g of Fe

4.-      160 g of Fe₂O₃  --------------- 3(44) g of CO₂

          400 g of Fe₂O₃  --------------  x

          x = (400 x 132)/160

         x = 330 gr

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Answer:

0.184 atm

Explanation:

The ideal gas equation is:

PV = nRT

Where<em> P</em> is the pressure, <em>V</em> is the volume, <em>n</em> is the number of moles, <em>R</em> the constant of the gases, and <em>T</em> the temperature.

So, the sample of N₂O₃ will only have its temperature doubled, with the same volume and the same number of moles. Temperature and pressure are directly related, so if one increases the other also increases, then the pressure must double to 0.092 atm.

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So, 1 mol of N₂O₃ will produce 2 moles of the products (1 of each), the <em>n </em>will double. The volume and the temperature are now constants, and the pressure is directly proportional to the number of moles, so the pressure will double to 0.184 atm.

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Answer: Adding a reactant will shift the reaction towards the products.

Adding a product will shift the reaction towards the reactants.

Removing a reactant will shift the reaction towards the reactants.

Removing a product will shift the reaction towards the products.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

Adding a reactant will increase the concentration of reactants and hence the reaction will try to undo the increase by shifting  the reaction towards the products.

Adding a product will increase the concentration of products and hence the reaction will try to undo the increase by shifting the reaction towards the reactants.

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