Answer:
A pipe open at both ends would have an antinode at each end and its length would be λ/ 2
The next such points would be λ and 3 λ / 2
The ratio of 522 / 348 is 1.5 so the harmonic at 348 is one wavelength and the next harmonic is 3 λ / 2 at 1 1/2 wavelengths
348 hz would occur at one wavelength
f λ = v = f L where the length of the pipe is one wavelength
if we use 331 as the speed of sound then
L = 331 / 348 = .95 m for the length of the pipe
Complete Question
The complete question is shown on the first uploaded image
Answer:
The pressure difference of the first bubble is 
The pressure difference of the second bubble is 
The pressure difference on the second bubble is higher than that of the first bubble so when the valve is opened pressure from second bubble will cause air to flow toward the first bubble making is bigger
Explanation:
From the question we are told that
The radius of the first bubble is 
The radius of the second bubble is 
The surface tension of the soap solution is 
Generally according to the Laplace's Law for a spherical membrane the pressure difference is mathematically represented as

Now the pressure difference for the first bubble is mathematically evaluated as

substituting values


Now the pressure difference for the second bubble is mathematically evaluated as



1) Gametophyte
2) Gametes
3) Zygote
4) Sporophyte
These are all related because they all help undergo mitosis, and are used in the Life Cycle of Plants.