How much work must be done on a 20-kg go-cart to increase its speed from 5 m/s to 10 m/s?
2 answers:
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Answer:
For 6.0 eV
0.5 nm, 1.45*10^6 m/s, 6.17*10^10 m/s, 1.45*10^6 m/s
For 600 eV
1.26*10^-3 nm, 2.66*10^8 m/s, 3.37*10^8 m/s, 2.66*10^8 m/s
Explanation:
See attachment for calculation
Answer:
Explanation:
We must use conservation of linear momentum before and after the collision,
Before the collision we have:
where these are the masses are initial velocities of both players.
After the collision we have:
since they clong together, acting as one body.
This means we have:
Or:
Which for our values is: