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2 years ago

What are the names of the components (each shown with a leader and a line) of a circuit shown in the diagram?

Physics

1 answer:

lys-0071 [83]2 years ago

5 0

Answer:

An Open circuit. (A BATTERY, BULB, WIRE, SWITCH)

Explanation:

The battery supplies the power, the wire carries the current from the battery to the bulb but the circuit is not complete if the switch is not connected (Closed).

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A small ranger vehicle has a soft, ragtop roof. When the car is at rest, the roof is flat. When the car is cruising at highway s

Nezavi [6.7K]

Answer:

roof bow upwards

Explanation:

The top of the roof of the small ranger vehicle will bow upwards. This is as a result of gas pressure on the soft ragtop roof.

As air begins to fill the vehicle, pressure resonates in all direction proportionally.
The pressure of the air will be greater than that which the roof can withstand and this forces the roof sky up.
It is a common scene when we see roof of ragtop vehicles bowing upwards into the sky.

5 0

3 years ago

Helppppppp its exam

UkoKoshka [18]

Answer:

a. 240.2 C

Explanation:

7 0

3 years ago

Using a rope that will snap if the tension in it exceeds 356 N, you need to lower a bundle of old roofing material weighing 478

klasskru [66]

Answer:

a) 2.5 m/s²

b) 6.12 m/s

Explanation:

Tension of rope = T = 356N

Weight of material = W = 478 N

Distance from the ground = s = 7.5 m

Acceleration due to gravity = g = 9.81 m/s²

Mass of material = m = 478/9.81 = 48.72

Final velocity before the bundle hits the ground = v

Initial velocity = u = 0

Acceleration experienced by the material when being lowered = a

a) W-T = ma

⇒478-356 = 48.72×a

$\Rightarrow \frac{122}{48.72} = a$

⇒a = 2.5 m/s²

∴ Acceleration achieved by the material is 2.5 m/s²

b) v²-u² = 2as

⇒v²-0 = 2×2.5×7.5

⇒v² = 37.5

⇒v = 6.12 m/s

∴ Velocity of the material before hitting the ground is 6.12 m/s

5 0

3 years ago

Two workers pull horizontally on a heavy box. but one pulls twice as hard as the other. The larger pull is directed at 21.0° wes

pantera1 [17]

Answer:

The magnitude of F1 is

$|F1|=358.74 \ N$

The magnitude of F2 is

$|F2|=179.37\ N$

And the direction of F2 is

$\alpha = 44.214^o$

Explanation:

<u>Net Force </u>

Forces are represented as vectors since they have magnitude and direction. The diagram of forces is shown in the figure below.

The larger pull F1 is directed 21° west of north and is represented with the blue arrow. The other pull F2 is directed to an unspecified direction (red arrow). Since the resultant Ft (black arrow) is pointed North, the second force must be in the first quadrant. We must find out the magnitude and angle of this force.

Following the diagram, the sum of the vector components in the x-axis of F1 and F2 must be zero:

$\displaystyle -2F\ sin21^o+F\ cos\alpha =0$