the equation of the tangent line must be passed on a point A (a,b) and
perpendicular to the radius of the circle. <span>
I will take an example for a clear explanation:
let x² + y² = 4 is the equation of the circle,
its center is C(0,0). And we assume that the tangent line passes to the point
A(2.3).
</span>since the tangent passes to the A(2,3), the line must be perpendicular to the radius of the circle.
<span>Let's find the equation of the line parallel to the radius.</span>
<span>The line passes to the A(2,3) and C (0,0). y= ax+b is the standard form of the equation. AC(-2, -3) is a vector parallel to CM(x, y).</span>
det(AC, CM)= -2y +3x =0, is the equation of the line // to the radius.
let's find the equation of the line perpendicular to this previous line.
let M a point which lies on the line. so MA.AC=0 (scalar product),
it is (2-x, 3-y) . (-2, -3)= -4+4x + -9+3y=4x +3y -13=0 is the equation of tangent
Answer:
since the direction of force is along south so the magnetic field must be upwards
Explanation:
Force on moving charge in magnetic field is given as
here we know this is force on proton
so we have
also we know that the velocity of charge is
now from above formula we have
since the direction of force is along south so the magnetic field must be upwards
Answer:
balanced?
Explanation:
because if it wasn't moving that means they are pulling at a similar strength
Answer:5.45X10^3m
Explanation:So use the formula,v= fλ
3X10^8=5.5X10^4λ what Im saying is divide both and u should get 5454.54m but do sig figs to get answer
