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Nonamiya [84]
3 years ago
5

Describe how a positive result for the Baeyer Test will look. What is being oxidized? What is being reduced?

Chemistry
1 answer:
Ksivusya [100]3 years ago
5 0

Answer:

This reaction is sometimes referred to as the Baeyer test. Because potassium permanganate, which is purple, is reduced to manganese dioxide, which is a brown precipitate, any water‐soluble compound that produces this color change when added to cold potassium permanganate must possess double or triple bonds.

Explanation:

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What  are the animals to choose from?

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3 years ago
g 10.00 mL of phosphoric acid (H3PO4) are titrated with 0.1000 M sodium hydroxide. 15.00 mL of the sodium hydroxide solution are
aliya0001 [1]

<u>Answer:</u> The molarity of phosphoric acid is 0.05 M

<u>Explanation:</u>

A neutralization reaction is defined as the reaction in which an acid reacts with a base to form a salt and water molecule.

At equivalence, moles of acid becomes equal to the moles of base. The equation for the neutralization follows:

n_1M_1V_1=n_2M_2V_2              ........(1)

where,

n_1, M_1\text{ and }V_1 are the n-factor, molarity and volume of acid that is H_3PO_4

n_2, M_2\text{ and }V_2 are the n-factor, molarity and volume of the base that is NaOH

Given values:

n_1=3\\M_1=?M\\V_1=10.00mL\\n_2=1\\M_2=0.1000M\\V_2=15.00mL

Plugging values in equation 1:

3\times M_1\times 10.00=1\times 0.1000\times 15.00\\\\M_1=\frac{1\times 0.1000\times 15.00}{3\times 10.00}\\\\M_1=0.05M

Hence, the molarity of phosphoric acid is 0.05 M

6 0
3 years ago
Classify methanol (ch3oh) as a strong electrolyte, a weak electrolyte, or a nonelectrolyte.
MrRa [10]
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8 0
4 years ago
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Water and heat the water to 50 C7
Wittaler [7]

Answer:

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Explanation:

The latent heat of water is 4.2J/g °C  so the energy needed to increase the tempearture from 80 °C to 100°C will be:

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40g * 2260J/g = 90,400J

The heat needed to increase steam temperature should be same as latent heat of water, 4.2J/g °C . So, the energy needed to increase temeprature from 100 to 180 will be:

40g * 4.2J/g °C * (180-100°C )= 13,440J

The total energy needed will be: 3,360J + 90,400J +13,440J= 107,200J

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4 years ago
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