Answer:
56.17% is percent composition of Sb in the molecule
Explanation:
Percent composition is the percent in mass of each element present in a particular molecule.
In SbF₅, there is 1 mole of Antimony -Molar mass: 121.76g- per 5 moles of fluorine -Molar mass: 19g/mol-. In a basis of 1 mole, the mass of Sb and F is:
<em>Mass Sb:</em>
1mol * (121.76g/mol) = 121.76g
<em>Mass F:</em>
1 mol SbF₅ = 5 moles F * (19g / mol) = 95g
<em>Total mass:</em>
121.76g + 95g = 216.76g
And percent composition of Sb:
121.76g / 216.76g * 100 =
<h3>56.17% is percent composition of Sb in the molecule</h3>
BaCO3=BaO+CO2
IS THE EQUATION REPLACE = WITH AN ARROW.
The symbol of helium is He and this distinguishes it from the symbol for hydrogen.
<h3>What are chemical symbols?</h3>
Chemical symbol are the means by which we designate elements on paper. The symbols could be one letter or two letter as the case may be. There is no chemical symbol that has more than two letters that are used to designate the element.
We know that hydrogen has the symbol H. There is to way that another element will also have the symbol H as that would be tantamount to confusion. As a result of that, the symbol of helium is He and this distinguishes it from the symbol for hydrogen.
Learn kore about chemical symbol:brainly.com/question/9249660
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The amount, in mL, of the concentrated acid required, would be 1.1875 mL
<h3>Dilution</h3>
From the dilution equation:
m1v1=m2v2 where m1 and m2 = molarity before and after dilution, and v1 and v2 = volume before and after dilution.
m2 = 0.285M, m1 = 12.0M v2 = 50.0 mL
v1 = m2v2/m1 = 0.285x50/12 = 1.1875 mL
Thus, 1.1875 mL of the acid would be taken and diluted with water up to the 50 mL mark.
More on dilution can be found here: brainly.com/question/13949222
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The atoms are constantly in motion
