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joja [24]
2 years ago
14

Imagine a beaker divided down the center by a rigid membrane that is freely permeable to water but impermeable to glucose. Side

1 contains a 10% glucose solution & side 2 contains the same volume of pure water. At equilibrium, what will be the situation?
1. water will continue to move from side 2 to side 1
2. the volume of liquid remain equal on both sides
3. water will continue to move from side 1 to side 2
4. the volume of liquid will be greater in side 2
5. the volume of liquid will be greater in side 1
Chemistry
1 answer:
damaskus [11]2 years ago
6 0

Answer:

D. The volume of liquid will be greater in side 1

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<em>3.27·10²³ atoms of O</em>

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To figure out the amount of oxygen atoms in this sample, we must first evaluate the sample.

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We will use stoichiometry to convert from our mass of <em>Na₂SO₄ </em>to moles of <em>Na₂SO₄</em>, and then from moles of <em>Na₂SO₄ </em>to moles of <em>O </em>using the mole ratio; then finally, we will convert from moles of <em>O </em>to atoms of <em>O </em>using Avogadro's constant.

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