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NARA [144]
3 years ago
10

A scientist wants to perform a controlled experiment to test the effect of rust on chemically treated iron. which action would b

e most important to perform in a controlled experiment? design an experiment that is based on previously published results. expose the treated iron to the corrosive effects of the air. test a large piece of treated iron and a small piece of untreated iron. test a piece of treated iron and a piece of untreated iron under the same conditions.
Chemistry
2 answers:
olga2289 [7]3 years ago
9 0
The answer is to test a piece of untreated and treated under same conditions!
Ilia_Sergeevich [38]3 years ago
8 0

Answer: Option (d) is the correct answer.

Explanation:

A test or experiment in which only one variable is changed at a time in order to verify the result is known as a controlled experiment.

That is only independent variable need to be adjusted with respect to the dependent variable.

Thus, we can conclude that the action to test a piece of treated iron and a piece of untreated iron under the same conditions would be most important to perform in a controlled experiment in the given situation.


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Consider the following reaction where Kc = 154 at 298 K.2NO(g) + Br2(g) 2NOBr(g)A reaction mixture was found to contain 4.64×10-
IgorLugansk [536]

Answer:

The reaction is not at equilibrium and reaction must run in forward direction.

Explanation:

At the given interval, concentration of NO = \frac{4.64\times 10^{-2}}{1}M=4.64\times 10^{-2}M

Concentration of Br_{2} = \frac{4.56\times 10^{-2}}{1}M=4.56\times 10^{-2}M

Concentration of NOBr = \frac{0.102}{1}M=0.102M

Reaction quotient,Q_{c} , for this reaction = \frac{[NOBr]^{2}}{[NO]^{2}[Br_{2}]}

species inside third bracket represents concentrations at the given interval.

So, Q_{c}=\frac{(0.102)^{2}}{(4.64\times 10^{-2})^{2}\times (4.56\times 10^{-2})}=106

So, the reaction is not at equilibrium.

As Q_{c}< K_{c} therefore reaction must run in forward direction to increase Q_{c} and make it equal to K_{c}.

4 0
3 years ago
Identify and calculate the number of representative particles in 2.15 moles of gold.<br>​
LekaFEV [45]

Answer:

1.29 * 10^{24} particles of gold

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To convert the number of moles of any substance, in this case gold, you need Avogadro's number.

Avogadro's number is always 6.022 × 10^{23}

2.15 moles Au × \frac{6.022*10^{23} particles}{1 mole Au} = 1.29 * 10^{24} particles of gold

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ratelena [41]

Answer:

the number off double bonds in a fatty acid chain

4 0
1 year ago
How are substances and mixtures different and alike???
nikklg [1K]

A mixture is composed of more than one substance combined
A pure substance cannot be decomposed in any reaction
<span>Both are considered types of substances 
</span>hope it helps you playa!

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The answer is B, nic fiss, nic fusi
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