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NARA [144]
2 years ago
10

A scientist wants to perform a controlled experiment to test the effect of rust on chemically treated iron. which action would b

e most important to perform in a controlled experiment? design an experiment that is based on previously published results. expose the treated iron to the corrosive effects of the air. test a large piece of treated iron and a small piece of untreated iron. test a piece of treated iron and a piece of untreated iron under the same conditions.
Chemistry
2 answers:
olga2289 [7]2 years ago
9 0
The answer is to test a piece of untreated and treated under same conditions!
Ilia_Sergeevich [38]2 years ago
8 0

Answer: Option (d) is the correct answer.

Explanation:

A test or experiment in which only one variable is changed at a time in order to verify the result is known as a controlled experiment.

That is only independent variable need to be adjusted with respect to the dependent variable.

Thus, we can conclude that the action to test a piece of treated iron and a piece of untreated iron under the same conditions would be most important to perform in a controlled experiment in the given situation.


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What phase(s) would you expect to observe when the substance is at a temperature of 275 kelvin?
pychu [463]
The phase of a substance at a temperature of 275 K or 1.85 degrees Celsius can be any of the three phases namely a solid, a liquid and a gas. This depends on the pressure where the substance is subjected. Also, the phase can be determined by a phase diagram where it shows the phase of a certain substance at a specific temperature and pressure.
4 0
2 years ago
a car is traveling at a speed of 55 mph the speed increased to 75 mph if the time needed to hange its speed is 4 seconds whats t
Savatey [412]

v = 75 mph = 33.52 m/s

u = 55 mph = 24.58 m/s

t = 4 sec

acceleration = v-u/t

= 33.52-24.58/4

= 8.94/4

= 2.235 m/s

6 0
3 years ago
The ability to attract an electron for bonding is called:
Darina [25.2K]
The ability to attract an electron for bonding is called (option B) Electronegativity.
4 0
2 years ago
How many moles of pcl5 can be produced from 28.0 g of p4 (and excess cl2)?
BARSIC [14]
P₄ + 10Cl₂ ---> 4PCl₅
stoichiometry of P₄ to PCl₅ is 1:4
number of moles of P₄ reacted - 28.0 g / 124 g/mol = 0.22 mol 
Cl₂ is in excess therefore P₄ is the limiting reactant, amount of product formed depends on amount of limiting reactant present 
according to molar ratio of 1:4
number of PCl₅ moles formed  -0.22 mol x 4 = 0.88 mol 
0.88 mol of PCl₅ is formed 

5 0
3 years ago
A fine of 50.0 mL of 0.0900 M CaCl2 reacts with excess sodium carbonate to give 0.366 g of calcium carbonate precipitate. What i
In-s [12.5K]

Answer:

81.26% is the percent yield

Explanation:

Based on the reaction:

CaCl₂ + Na₂CO₃ → 2NaCl + CaCO₃

<em>Where 1 mole of CaCl₂ in excess of sodium carbonate produces 1 mole of calcium carbonate.</em>

<em />

To solve this question we must find the moles of CaCl2 added = Moles CaCO₃ produced (Theoretical yield). The percent yield is:

Actual yield (0.366g) / Theoretical yield * 100

<em>Moles CaCl₂ = Moles CaCO₃:</em>

0.0500L * (0.0900moles / L) = 0.00450 moles of CaCO₃

<em>Theoretical mass -Molar mass CaCO₃ = 100.09g/mol-:</em>

0.00450 moles of CaCO₃ * (100.09g / mol) = 0.450g of CaCO₃

Percent yield = 0.366g / 0.450g * 100

81.26% is the percent yield

3 0
2 years ago
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