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NARA [144]
3 years ago
10

A scientist wants to perform a controlled experiment to test the effect of rust on chemically treated iron. which action would b

e most important to perform in a controlled experiment? design an experiment that is based on previously published results. expose the treated iron to the corrosive effects of the air. test a large piece of treated iron and a small piece of untreated iron. test a piece of treated iron and a piece of untreated iron under the same conditions.
Chemistry
2 answers:
olga2289 [7]3 years ago
9 0
The answer is to test a piece of untreated and treated under same conditions!
Ilia_Sergeevich [38]3 years ago
8 0

Answer: Option (d) is the correct answer.

Explanation:

A test or experiment in which only one variable is changed at a time in order to verify the result is known as a controlled experiment.

That is only independent variable need to be adjusted with respect to the dependent variable.

Thus, we can conclude that the action to test a piece of treated iron and a piece of untreated iron under the same conditions would be most important to perform in a controlled experiment in the given situation.


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HELP PLEASEEEEEEEEEEEEEEEEEEE
Korolek [52]

Answer:

1-air

2-decrease

3-water

4-gas

5-liquid

I THINK the answer to part b is A but I am not entirely sure

Explanation:

5 0
2 years ago
1. The gases SO2, O2 and SO3 are allowed to reach equilibrium at a constant temperature. The equilibrium constant for the reacti
irina [24]

Answer:

a)

K_2=1.3x10^{2}atm^{-1/2}

b)

PCl_5\rightarrow PCl_3+Cl_2

[PCl_5]=0.0375M

Explanation:

Hello!

a) In this case, since we can see that the second reaction is equal to the half of the first reaction, we can relate the equilibrium constants as shown below:

K_2=K_1^{1/2}

Thus, by plugging in the the equilibrium constant of the first reaction we obtain:

K_2=(1.6x10^4atm^{-1})^{1/2}\\\\K_2=1.3x10^{2}atm^{-1/2}

b) In this case, for the described reaction we can write:

PCl_5\rightarrow PCl_3+Cl_2

Thus, the corresponding equilibrium expression is:

K=\frac{[PCl_3][Cl_2]}{[PCl_5]}

In such a way, since we know the equilibrium constant and the concentrations of PCl3 and Cl2 at equilibrium, we can compute the concentration of PCl5 at equilibrium as follows:

[PCl_5]=\frac{[PCl_3][Cl_2]}{K}\\

[PCl_5]=\frac{\frac{0.20mol}{4L} *\frac{0.12mol}{4L} }{0.04}

[PCl_5]=0.0375M

Best regards!

7 0
2 years ago
Why is it impossible for a machine to give you more energy output than the amount of energy put into it?
lana66690 [7]
Ambersnyder, Your answer would be A).
5 0
3 years ago
I need help please and thank you! Also if you found the answer can you explain how you did, like wat did u search for...if it’s
belka [17]

Answer:

C.  

Explanation:

Stereoisomers are molecules that have the same molecular formula and with their atoms connected in the same way but pointing in different directions.

<em>cis</em>-Pent-2-ene has formula C₅H₁₀

A. is wrong, because its formula is C₅H₁₂

B. and D. are wrong, because their formulas are C₅H₈

The only option left is C. It has formula C₅H₁₀

C. is a stereoisomer of <em>cis</em>-pent-2-ene, because atoms 1 and 4 are on opposite sides of the double bond.

Think of the C=C bond as a river.

In the <em>cis </em>isomer (top), atoms 1 and 4 are on the same side of the river (zis = zame zide).

In the <em>trans</em> isomer (bottom), atoms 1 and 4 are on opposite sides of the river (trans = across or opposite).

So, C. is a stereoisomer of cis-pent-2-ene.

8 0
3 years ago
What is oxidized in an electrolytic cell with aluminum and gold electrodes?
irina [24]

Answer:

The answer is B The aluminum metal.

Explanation:

have a wonderful day! do good in school you got this! :)

4 0
2 years ago
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