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3 years ago

What is the formula for Dicarbon trioxide

Chemistry

1 answer:

Veronika [31]3 years ago

4 0

Answer:

diboron trioxide Formula: B 2 O 3 Molecular weight: 69.620 CAS Registry Number: 1303-86-2

Explanation:

<h3><u><em>hope that helps you</em></u>╰(*°▽°*)╯</h3>

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What are the gas laws? (Include Boyle's law, charles's law, gay lussac's law, an avogadro's law) Could someone please summarize

Rina8888 [55]

Answer:

Boyle's Law: When the pressure of a gas increases, the volume of the gas will decrease as long as the temperature and amount of gas are constant.

So basically pressure is inversely proportional to Volume, when one increases, the other decreases, vice versa.

Equation: $P_{1} V_{1} = P_{2} V_{2}$

Charles Law: When the temperature of a gas increases, the volume of a gas will also increase if the pressure and amount of gas are constant.

So basically Temperature and volume are directly proportional.

Equation: $\frac{V_{1}}{T_{1}} = \frac{V_{2} }{T_{2} }$

Gay Lussac's Law: When the temperature of a gas increases, the pressure of a gas also increases when volume and the amount of gas remain constant.

Basically, Temperature and Pressure are directly proportional.

Equation: $\frac{P_{1}}{T_{1}} = \frac{P_{2} }{T_{2} }$

Avogadro's Law: The most intuitive gas law. When you increase the amount of gas, the volume will also increase.

Meaning the moles (amount of gas) is directly proportional to volume.

Equation: $\frac{V_{1} }{n_{1} } = \frac{V_{2} }{n_{2} }$ (n stands for moles)

There is a combined gas law and ideal gas law but those are just the gas laws mentioned above but combined together. These should be everything.

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2 years ago

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Which of these is a benefit of including comments in your code

morpeh [17]

A benefit of including comments in your code is that it helps other programmers understand your code.

These are numbers and letters which are used to identify a particular thing at a point in time.

Comments can be put in a code so as to enable others know and understand real intentions about it etc.

Read more about Code here brainly.com/question/2217700

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3 years ago

How does the solubility of a gas change with decreasing temperature?

dem82 [27]

It increases..........

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4 years ago

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Describe 3 properties of a frozen fruit far including state of matter

miv72 [106K]

Nucleic Acids, Protein Coat,and Lipid Membrane

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4 years ago

A gas mixture at 535.0°C and 109 kPa absolute enters a heat exchanger at a rate of 67.0 m3/hr. The gas leaves the heat exchanger

SVEN [57.7K]

Answer:

the heat rate required to cool down the gas from 535°C until 215°C is -2.5 kW.

Explanation:

assuming ideal gas behaviour:

PV=nRT

therefore

P= 109 Kpa= 1.07575 atm

V= 67 m3/hr = 18.6111 L/s

T= 215 °C = 488 K

R = 0.082 atm L /mol K

n = PV/RT = 109 Kpa = 1.07575 atm * 18.611 L/s /(0.082 atm L/mol K * 488 K)

n= 0.5 mol/s

since the changes in kinetic and potencial energy are negligible, the heat required is equal to the enthalpy change of the gas:

Q= n* Δh = 0.5 mol/s * (- 5 kJ/mol) =2.5 kW

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3 years ago