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lana [24]
3 years ago
13

Myoncedyret

Physics
1 answer:
konstantin123 [22]3 years ago
8 0

Answer:

i need help too

Explanation:

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An archer puts a 0.30-kg arrow to the bowstring. An average force of 201 N is exerted to draw the string back 1.3 m. Assuming th
vovikov84 [41]

Answer:

41.74 m/s

Explanation:

The energy used to draw the bowstring = the kinetic energy of the arrow.

Fd = 1/2mv²................................ Equation 1

Where F = force, d = distance move string, m = mass of the arrow, v = speed of the arrow.

make v the subject of the equation

v = √(2Fd/m)...................... Equation 2

Given: F = 201 N, m = 0.3 kg, d = 1.3 m.

Substitute into equation 2

v = √(2×201×1.3/0.3)

v = √(1742)

v = 41.74 m/s.

Hence the arrow leave the bow with a speed of 41.74 m/s

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3 years ago
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OK brainly if you want hard here here are sixty cups on a table. If one falls down, then how many remain
vivado [14]

Answer:

If one cup falls down then there will be 59 cups left.

5 0
4 years ago
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A small charged bead has a mass of 1.9 g . it is held in a uniform electric field e⃗ = (200,000 n/c, up). when the bead is relea
dmitriy555 [2]

As we know that when charge is released in electric field

It will have two forces on it

1. electrostatic force

2. gravitational force

now if the ball will accelerate upwards so we can say

net upward force = mass * acceleration

qE - mg = ma

q*200000 - 1.9 * 10^{-3}* 9.8 = 1.9 * 10^{-3}* 15

now we can find charge q on it by above equation

q = 0.2356 * 10^{-6} C

So above is the charge on the particle

7 0
3 years ago
A motorist makes a trip of 180 miles. For the first 90 mph she drives at a constant speed of 30 mph. What constant speed must sh
Likurg_2 [28]
I think it is 50 mhp because it's in half
5 0
3 years ago
In a drill during basketball practice, a player runs the length of the 30-meter court and back. The player does this three times
Sergeeva-Olga [200]

Answer:

0 m/s

Explanation:

Average velocity of an object is given by the net displacement divided by time taken. Displacement is equal to the shortest path covered by the object.

In this problem, a player runs the length of the 30-meter court and back. The player does this three times in 60 seconds.

As the player runs the court and returns to the original point. It would mean that the shortest path covered is 0.

Average velocity = displacement/time

v=0/30

v = 0 m/s

Hence, the correct option is (1).

6 0
3 years ago
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