Answer:
- <em>The solution expected to contain the greatest number of solute particles is: </em><u>A) 1 L of 1.0 M NaCl</u>
Explanation:
The number of particles is calculated as:
a) <u>For Ionic compounds</u>:
- molarity × volume in liters × number of ions per unit formula.
b) <u>For covalent compounds</u>:
- molarity × volume in liters
The difference is a factor which is the number of particles resulting from the dissociation or ionization of one mole of the ionic compound.
So, calling M the molarity, you can write:
- # of particles = M × liters × factor
This table show the calculations for the four solutions from the list of choices:
Compound kind Particles in solution Molarity # of particles
(dissociation) (M) in 1 liter
A) NaCl ionic ions Na⁺ and Cl⁻ 1.0 1.0 × 1 × 2 = 2
B) NaCl ionic ions Na⁺ anc Cl⁻ 0.5 0.5 × 1 × 2 = 1
C) Glucose covalent molecules 0.5 0.5 × 1 × 1 = 0.5
D) Glucose covalent molecules 1.0 1.0 × 1 × 1 = 1
Therefore, the rank in increasing number of particles is for the list of solutions given is: C < B = D < A, which means that the solution expected to contain the greatest number of solute particles is the solution A) 1 L of 1.0 M NaCl.
Density is defined as mass per unit volume
therefore density = mass ÷ volume
volume = mass÷density
volume in ml = 17 ÷ 3.291
The theobromine molecule contains a total of 22 bonds
The number of mole of NaOH that was used, given that 3.85 mL of 10.0 M NaOH is used in the reaction is 0.0385 mole
<h3>How do I determine the number of mole of NaOH?</h3>
We know that molarity is related to number of mole and volume according to the following formula:
Molarity = number of mole / Volume
With the above formula, we can determine the number of mole of NaOH. Details below
The following data were obtained from the question:
- Volume = 3.85 mL = 3.85 / 1000 = 0.00385 L
- Molarity = 10.0 M
- Number of mole of NaOH =?
Molarity = number of mole / Volume
Cross multiply
Number of mole = molarity × volume
Number of mole of NaOH = 10 × 0.00385
Number of mole of NaOH = 0.0385 mole
Thus, the number of mole of NaOH is 0.0385 mole
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